如果我匹配一个单独的键，那么迭代这个数据集返回来自另一个键值对的所有匹配值的最佳方法是什么？

Question

我希望能够搜索这个列表(见文章的底部)的dicts (我认为这是这个特殊的安排是什么)搜索一个‘地址’匹配‘0xd 2’。如果找到匹配，我希望返回/打印所有相应的id。

因此，在这种情况下，我想返回: 632,315,432,100

我能够提取出这样的单个值：

none = None
print(my_dict['result'][2]["id"])

432

我很难找到一个循环来正确地做这件事。

{
  "total": 4,
  "page": 0,
  "page_size": 100,
  "result": [
    {
      "address": "0xd2",
      "id": "632",
      "amount": "1",
      "name": "Avengers",
      "group": "Marvel",
      "uri": "https://google.com/",
      "metadata": null,
      "synced_at": "2022-05-26T22:52:34.113Z",
      "last_sync": "2022-05-26T22:52:34.113Z"
    },
    {
      "address": "0xd2",
      "id": "315",
      "amount": "1",
      "name": "Avengers",
      "group": "Marvel",
      "uri": "https://google.com/",
      "metadata": null,
      "synced_at": "2022-05-26T22:52:34.113Z",
      "last_sync": "2022-05-26T22:52:34.113Z"
    },
    {
      "address": "0xd2",
      "id": "432",
      "amount": "1",
      "name": "Avengers",
      "group": "Marvel",
      "uri": "https://google.com/",
      "metadata": null,
      "synced_at": "2022-05-26T22:52:34.113Z",
      "last_sync": "2022-05-26T22:52:34.113Z"
    },
{
      "address": "0x44",
      "id": "100",
      "amount": "1",
      "name": "Suicide Squad",
      "group": "DC",
      "uri": "https://google.com/",
      "metadata": null,
      "synced_at": "2022-05-26T22:52:34.113Z",
      "last_sync": "2022-05-26T22:52:34.113Z"
    }
  ],
  "status": "SYNCED"
}

Answer 1

欢迎来到StackOverflow。

你可以试着理解列表：

[res["id"] for res in my_dict["result"] if res["address"] == "0xd2"]

如果您想使用for循环：

l = []
for res in my_dict["result"]:
    if res["address"] == "0xd2":
        l.append(res["id"])

Answer 2

你可以使用列表理解。

import json

json_string = """{
  "total": 4,
  "page": 0,
  "page_size": 100,
  "result": [
    {
      "address": "0xd2",
      "id": "632",
      "amount": "1",
      "name": "Avengers",
      "group": "Marvel",
      "uri": "https://google.com/",
      "metadata": null,
      "synced_at": "2022-05-26T22:52:34.113Z",
      "last_sync": "2022-05-26T22:52:34.113Z"
    },
    {
      "address": "0xd2",
      "id": "315",
      "amount": "1",
      "name": "Avengers",
      "group": "Marvel",
      "uri": "https://google.com/",
      "metadata": null,
      "synced_at": "2022-05-26T22:52:34.113Z",
      "last_sync": "2022-05-26T22:52:34.113Z"
    },
    {
      "address": "0xd2",
      "id": "432",
      "amount": "1",
      "name": "Avengers",
      "group": "Marvel",
      "uri": "https://google.com/",
      "metadata": null,
      "synced_at": "2022-05-26T22:52:34.113Z",
      "last_sync": "2022-05-26T22:52:34.113Z"
    },
{
      "address": "0x44",
      "id": "100",
      "amount": "1",
      "name": "Suicide Squad",
      "group": "DC",
      "uri": "https://google.com/",
      "metadata": null,
      "synced_at": "2022-05-26T22:52:34.113Z",
      "last_sync": "2022-05-26T22:52:34.113Z"
    }
  ],
  "status": "SYNCED"
}"""

json_dict = json.loads(json_string)

result = [elem['id'] for elem in json_dict['result'] if elem['address'] == '0xd2']

print(result)

输出：

['632', '315', '432']

Answer 3

这将在列表中存储相关的in：

ids=[]
for r in dataset.get('result'):
    if r.get('address')=='0xd2':
        ids.append(r.get('id'))