我有四个外勤部
dfB = pd.DataFrame([[cheapest_brandB[0],wertBereichB]], columns=['brand', 'price'], index=
['cheap'])
dfC = pd.DataFrame([[cheapest_brandC[0],wertBereichC]], columns=['brand', 'price'], index=
['cheap'])
dfG = pd.DataFrame([[cheapest_brandG[0],wertBereichG]], columns=['brand', 'price'], index=
['cheap'])
dfO = pd.DataFrame([[cheapest_brandO[0],wertBereichO]], columns=['brand', 'price'], index=
['cheap'])结果:
brand price
cheap ASUS {'gte': 821.84, 'lte': 1200.91}
brand price
cheap HP {'gte': 187.82, 'lte': 993.73}
brand price
cheap Google {'gte': 1047.3, 'lte': 2093.59}
brand price
cheap MSI {'gte': 1047.3, 'lte': 2093.59}我想要制作3d df,以便它们每个都属于一个特定的索引,就像这样。
Gaming Casual ....
brand price brand price
cheap ASUS {'gte': 821.84, 'lte': 1200.91} HP {'gte': 187.82, 'lte': 993.73} ....
light .. .. .. ..发布于 2022-07-03 17:23:24
在您提供的数据文件中:
import pandas as pd
dfs = [
pd.DataFrame(
{"brand": ["ASUS"], "price": [{"gte": 821.84, "lte": 1200.91}]}, index=["cheap"]
),
pd.DataFrame(
{"brand": ["HP"], "price": [{"gte": 187.82, "lte": 993.73}]}, index=["cheap"]
),
pd.DataFrame(
{"brand": ["Google"], "price": [{"gte": 1047.3, "lte": 2093.59}]},
index=["cheap"],
),
pd.DataFrame(
{"brand": ["MSI"], "price": [{"gte": 1047.3, "lte": 2093.59}]}, index=["cheap"]
),
]有一种方法可以做到:
for df, name in zip(dfs, ["Gaming", "Casual", "Pro", "Other"]):
df.columns = pd.MultiIndex.from_product([[name], ["brand", "price"]])
df = pd.concat(dfs, axis=1)因此:
print(df)
# Output
Gaming Casual \
brand price brand
cheap ASUS {'gte': 821.84, 'lte': 1200.91} HP
Pro \
price brand
cheap {'gte': 187.82, 'lte': 993.73} Google
Other
price brand price
cheap {'gte': 1047.3, 'lte': 2093.59} MSI {'gte': 1047.3, 'lte': 2093.59} https://stackoverflow.com/questions/72772472
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