向模拟构造函数中注入模拟依赖项

Question

如何模拟_SqsService.getSqsQueueURL的返回值？这是编译的，但是函数返回未定义的。我需要将sqsMocked注入sqsServiceMocked吗？如果是这样的话，是怎么做的？

测试：

jest.mock('aws-sdk');
jest.mock('../../../lambda-resources/AWS/Services/SQSService');
import { SQS, Request, Service, AWSError } from 'aws-sdk';
import { mockDeep, DeepMockProxy } from 'jest-mock-extended';
import { GetQueueUrlResult } from 'aws-sdk/clients/sqs';
import { SQSService } from '../../../lambda-resources/AWS/Services/SQSService';

let sqsMocked: DeepMockProxy<SQS>;
let sqsServiceMocked: DeepMockProxy<SQSService>;

beforeEach(async () => {
    sqsMocked = mockDeep<SQS>();
    sqsServiceMocked = mockDeep<SQSService>();

    sqsMocked.getQueueUrl.mockReturnValue(new Request<GetQueueUrlResult, AWSError>(new Service(), 'test'));
    sqsServiceMocked.getSqsQueueUrl.mockResolvedValue(Promise.resolve('test'));

test('getSqsQueueUrl should...', async () => {
    // It works when called directly from the unit test file, but not when called from the system under test in the code base itself
    expect(await sqsServiceMocked.getSqsQueueUrl('a')).toBe('test');          await (await LeadsCreator({}, {}))
    ...

正在测试的系统：

const AWSSqs = new AWS.SQS();
const _SqsService = new SQSService(AWSSqs);  

const response = await _SqsService.getSqsQueueUrl("x");

"jest": "^26.4.2",
"jest-mock-extended": "^2.0.6",

响应未定义

Answer 1

我还没有想出通过模仿它来实现这个工作的方法，所以我现在已经修改了原型。如果你有更好的建议，请分享

jest.mock('../../../lambda-resources/AWS/Services/SQSService');
import { SQSService } from '../../../lambda-resources/AWS/Services/SQSService';

test('getSqsQueueUrl should...', async () => {    
    SQSService.prototype.getSqsQueueUrl = (() => Promise.resolve(''));
...


afterEach(() => {
    delete SQSService.prototype.getSqsQueueUrl;
});