Python新的多个列表，没有重复。所有新列表都与第一个新列表对齐。

Question

当前产出：

['Jay', 'Boon', 'Sue', 'Tim', 'Lia', 'John', 'Abe']
[]
[]

理想产出：

['Jay', 'Boon', 'Sue', 'Tim', 'Lia', 'John', 'Abe']
[20,     40,    ,26,    28,     21,    91,     25]
[...]

NamesFromForum = ['Jay','Boon','Jay','Sue','Tim','Lia','Lia','John','John','Abe']
AgesFromForum = [20,40,30,26,28,21,18,91,10,25]
LocFromForum = ['BA','CA','NM','CO','AL','NY','TX','NV','MN','SO']

NameNoDup = []
ageAlignName = []
LocAlignName =[]

for x in NamesFromForum:
    if x not in NameNoDup:
        NameNoDup.append(x)

for y in AgesFromForum:
    for x in NamesFromForum:
        if x not in NameNoDup:
            AgesFromForum.append(y)

for z in LocFromForum:
    for x in NamesFromForum:
        if x not in NameNoDup:
            LocFromForum.append(z)


print(NameNoDup)
print(ageAlignName)
print(LocAlignName)```

Answer 1

最好使用控件集来确保不添加重复的名称，而不是每次扫描列表(速度更快)。然后使用zip对齐列表。就像这样：

NamesFromForum = ['Jay','Boon','Jay','Sue','Tim','Lia','Lia','John','John','Abe']
AgesFromForum = [20,40,30,26,28,21,18,91,10,25]
LocFromForum = ['BA','CA','NM','CO','AL','NY','TX','NV','MN','SO']

NameNoDup = []
ageAlignName = []
LocAlignName =[]

nameSet = set()

for name, age, loc in zip(NamesFromForum, AgesFromForum, LocFromForum):
    if name not in nameSet:
        NameNoDup.append(name)
        ageAlignName.append(age)
        LocAlignName.append(loc)
        nameSet.add(name)

print(NameNoDup)
print(ageAlignName)
print(LocAlignName)

输出：

['Jay', 'Boon', 'Sue', 'Tim', 'Lia', 'John', 'Abe']
[20, 40, 26, 28, 21, 91, 25]
['BA', 'CA', 'CO', 'AL', 'NY', 'NV', 'SO']