如何使用sed替换shell脚本中的cron？

Question

我需要使用sed或awk替换文件中的cron条目。

试过这个:没起作用

sed -i 's/0 0 * * 0/0 1 * * 1/g' script.sh

script.sh

#!/bin/bash

mkdir -p .github/workflows

cd .github/workflows
touch semgrep.yml

cat << EOF > semgrep.yml
name: Semgrep
on:
  pull_request: {}
  push:
    branches:
      - master
      - main
    paths:
      - .github/workflows/semgrep.yml
  schedule:
    - cron: '0 0 * * 0'
jobs:
  semgrep:
    name: Static Analysis Scan
    runs-on: ubuntu-18-04

请帮我同样的忙。

Answer 1

使用mikefarah/yq编辑文件就位(-i)：

yq -i '.on.schedule[].cron = "0 1 * * 1"' semgrep.yml

将打开包含以下内容的semgrep.yml

name: Semgrep
on:
  pull_request: {}
  push:
    branches:
      - master
      - main
    paths:
      - .github/workflows/semgrep.yml
  schedule:
    - cron: '0 0 * * 0'
jobs:
  semgrep:
    name: Static Analysis Scan
    runs-on: ubuntu-18-04

变成一个包含

name: Semgrep
on:
  pull_request: {}
  push:
    branches:
      - master
      - main
    paths:
      - .github/workflows/semgrep.yml
  schedule:
    - cron: '0 1 * * 1'
jobs:
  semgrep:
    name: Static Analysis Scan
    runs-on: ubuntu-18-04