Javascript:合并对象数组

Question

我有一个带有嵌套对象的对象数组，如下所示：

[
  {
    "metric1": 4.1,
    "addons": {
      "call_uuid_1": "13d1e097-0363-4a81-b9e4-85c6a770cdb2",
      "ThisDN_1": "50002",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric2": -12345.123412341234,
    "addons": {
      "call_uuid_2": "13d1e097-0363-4a81-b9e4-85c6a770cdb3",
      "ThisDN_2": "50003",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric3": -2345.123412341234,
    "addons": {
      "call_uuid_1": "13d1e097-0363-4a81-b9e4-85c6a770cdb2",
      "ThisDN_1": "50002",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric4": -345.12341234123414,
    "addons": {
      "call_uuid_2": "13d1e097-0363-4a81-b9e4-85c6a770cdb3",
      "ThisDN_2": "50003",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  }
]

我希望将一些数组对象与相同的嵌套对象addons合并，以便前面的数组变成：

[
  {
    "metric1": 4.1,
    "metric3": -2345.123412341234,
    "addons": {
      "call_uuid_1
": "13d1e097-0363-4a81-b9e4-85c6a770cdb2",
      "ThisDN_1": "50002",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric2": -12345.123412341234,
    "metric4": -345.12341234123414,
    "addons": {
      "call_uuid_2": "13d1e097-0363-4a81-b9e4-85c6a770cdb3",
      "ThisDN_2": "50003",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  }
]

有什么办法可以做到吗？

Answer 1

如果数组有多个具有相同addons对象的元素，则可以删除第一个元素的addons对象，然后将其与其他元素合并。

for (let i = 0; i < arr.length; i++) {
  for (let j = i + 1; j < arr.length; j++) {
    if (JSON.stringify(arr[i]["addons"]) === JSON.stringify(arr[j]["addons"])) {
      delete arr[i]["addons"];
      Object.assign(arr[i], arr[j]);
      arr.splice(j, 1);
      j -= 1;
    }
  }
}

输出：

[
  {
    metric1: 4.1,
    metric3: -2345.123412341234,
    addons: {
      call_uuid_1: '13d1e097-0363-4a81-b9e4-85c6a770cdb2',
      ThisDN_1: '50002',
      call_uuid: '13d1e097-0363-4a81-b9e4-85c6a770cdb4',
      ThisDN: '50004'
    }
  },
  {
    metric2: -12345.123412341234,
    metric4: -345.12341234123414,
    addons: {
      call_uuid_2: '13d1e097-0363-4a81-b9e4-85c6a770cdb3',
      ThisDN_2: '50003',
      call_uuid: '13d1e097-0363-4a81-b9e4-85c6a770cdb4',
      ThisDN: '50004'
    }
  }
]

Answer 2

可以使用JSON.stringify在addons对象中查找等式，然后合并对象。如下所示：

const array = [
  {
    "metric1": 4.1,
    "addons": {
      "call_uuid_1": "13d1e097-0363-4a81-b9e4-85c6a770cdb2",
      "ThisDN_1": "50002",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric2": -12345.123412341234,
    "addons": {
      "call_uuid_2": "13d1e097-0363-4a81-b9e4-85c6a770cdb3",
      "ThisDN_2": "50003",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric3": -2345.123412341234,
    "addons": {
      "call_uuid_1": "13d1e097-0363-4a81-b9e4-85c6a770cdb2",
      "ThisDN_1": "50002",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric4": -345.12341234123414,
    "addons": {
      "call_uuid_2": "13d1e097-0363-4a81-b9e4-85c6a770cdb3",
      "ThisDN_2": "50003",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  }
];

const mergedArray = [];
const addonsToIndexMap = {};

array.forEach(item => {
 const stringifyAddon = JSON.stringify(item.addons);    
 let indexInTheMap = addonsToIndexMap[stringifyAddon];
 if(indexInTheMap !== undefined) {
   mergedArray[indexInTheMap] = {...mergedArray[indexInTheMap], ...item};
 } else {
   mergedArray.push(item);
   addonsToIndexMap[stringifyAddon] = mergedArray.length - 1;
 }
});
console.log(mergedArray);

addonsToIndexMap的使用只是为了优化目的。注意：这个方法只有在addon对象中的键顺序相同的情况下才能工作。此外，我还更正了程序中的输入，以便使用call_uuid_1更新键call_uuid_1，以获得预期的输出，如注释中所述。请作相应的修改。