下面有个密码。我想删除突出显示部分之前的空白。

\documentclass[10pt,english,8pt]{beamer}
\usetheme{default}
\usepackage{booktabs}
\usepackage{tabularx}
%\newcommand{\iid}{\stackrel{\mathrm{iid}}{\sim}}
\newcolumntype{C}{>{\centering\arraybackslash}X}
\newcolumntype{R}{>{\raggedright\arraybackslash}X}
\newcolumntype{L}{>{\raggedleft\arraybackslash}X}
\title{Beamer Template}
\author{TeXstudio Team}
\begin{document}
\begin{frame}{Frame Title}
\begin{table}[htbp]
%\begin{table}[!ht]
\centering
\scriptsize
%\caption{Title }
\label{tab:5}
\begin{tabularx}{1\textwidth}
{>{\raggedright\arraybackslash}p{2cm}
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
}
%\multicolumn{11}{@{}p{1\textwidth}@{}}{\footnotesize
% Caption }\\
\toprule
& Log Probability of Default & Log Recovery Rate
& Log Spread & Log Leverage \\ [0.5ex]
& (1) & (2) & (3) & (4) \\
\midrule
Log Damage
&0.017** &-0.003*** & 0.002 & -0.157 \\
&(0.0008) &(0.003) & (0.075) & (0.178) \\
Log Adaptation
&-0.157*** &0.012 &-0.463** & 0.514*** \\
&(0.021) &(0.007) &(0.182) &(0.193)\\
Log Damage X Log Adaptation
&0.006 &0.018* &-0.398 &0.535 \\
&(0.030) &(0.011) &(0.249) &(0.513)\\
Constant
&-1.227***&-0.117***&2.244***&0.101\\
&(0.026)&(0.009)&(0.187)&(0.237)\\
\midrule
Observations &926 &925 &458 &177 \\
$R^2$ &41\% &19\% &8\% &38\%\\
Adjusted $R^2$ &40\%&17\%&4\%&32\%\\
Residual Std. Error
& 0.071 & 0.025 & 0.373 & 0.264 \\
& (df = 907) & (df = 906) & (df = 439) & (df = 159)\\
F Statistic
& 35.253*** & 11.455*** & 2.104*** & 5.811*** \\
& (df = 18; 907)& (df = 18; 906)& (df = 18; 439)& (df = 17; 159)\\
\bottomrule
\addlinespace
\multicolumn{4}{@{}p{0.8\textwidth}@{}}{\footnotesize \tiny{Note: *p<0.1; **p<0.05; ***p<0.01 }} \\
\end{tabularx}
%\end{table}
\end{table}
\end{frame}
\end{document}发布于 2022-06-01 11:09:50
Log Damage X Log Adaptation太长,不能容纳单个细胞。最简单的解决方法是手动将短语的第二部分移到下一行。如果使用的是
X列,以确保表能够适应可用的空间。
@{},以消除额外的空间为了使
块之间添加一些额外的垂直空间
X作为乘法符号吗?别这样!\tiny{...}是错误的。这是一个转换,不需要争论。使用{\tiny ...}代替.< signs的数学模式
\documentclass[10pt,english,8pt]{beamer}
\usetheme{default}
\usepackage{booktabs}
\usepackage{tabularx}
%\newcommand{\iid}{\stackrel{\mathrm{iid}}{\sim}}
\newcolumntype{C}{>{\centering\arraybackslash}X}
\newcolumntype{R}{>{\raggedright\arraybackslash}X}
\newcolumntype{L}{>{\raggedleft\arraybackslash}X}
\title{Beamer Template}
\author{TeXstudio Team}
\begin{document}
\begin{frame}{Frame Title}
\begin{table}[htbp]
%\begin{table}[!ht]
\centering
\scriptsize
%\caption{Title }
\label{tab:5}
\begin{tabularx}{1\textwidth}
{
@{}
>{\raggedright\arraybackslash}X
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
>{\centering\arraybackslash}p{1.75cm}
@{}
}
%\multicolumn{11}{@{}p{1\textwidth}@{}}{\footnotesize
% Caption }\\
\toprule
& Log Probability of Default & Log Recovery Rate
& Log Spread & Log Leverage \\ [0.5ex]
& (1) & (2) & (3) & (4) \\
\midrule
Log Damage
&0.017** &-0.003*** & 0.002 & -0.157 \\
&(0.0008) &(0.003) & (0.075) & (0.178) \\\addlinespace
Log Adaptation
&-0.157*** &0.012 &-0.463** & 0.514*** \\
&(0.021) &(0.007) &(0.182) &(0.193)\\\addlinespace
Log Damage $\times$
&0.006 &0.018* &-0.398 &0.535 \\
Log Adaptation &(0.030) &(0.011) &(0.249) &(0.513)\\\addlinespace
Constant
&-1.227***&-0.117***&2.244***&0.101\\
&(0.026)&(0.009)&(0.187)&(0.237)\\
\midrule
Observations &926 &925 &458 &177 \\
$R^2$ &41\% &19\% &8\% &38\%\\
Adjusted $R^2$ &40\%&17\%&4\%&32\%\\\addlinespace
Residual Std. Error
& 0.071 & 0.025 & 0.373 & 0.264 \\
& (df = 907) & (df = 906) & (df = 439) & (df = 159)\\\addlinespace
F Statistic
& 35.253*** & 11.455*** & 2.104*** & 5.811*** \\
& (df = 18; 907)& (df = 18; 906)& (df = 18; 439)& (df = 17; 159)\\
\bottomrule
\addlinespace
\multicolumn{4}{@{}p{0.8\textwidth}@{}}{\footnotesize {\tiny Note: *$p<0.1$; **$p<0.05$; ***$p<0.01$ }} \\
\end{tabularx}
%\end{table}
\end{table}
\end{frame}
\end{document}

https://stackoverflow.com/questions/72460770
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