需要收到200份来自航班搜索的推荐，使用java代码为循环地图功能提供放心。

Question

我需要收到300个建议在一个简短的使用for循环使用我的代码。

目前我可以收到一到十条推荐信的回复。但是当我处理200到500个建议时，我很难将代码从1编辑到500。相反，我尝试在代码中实现for循环，但是失败了。

下面是我的密码。

Map<String, String> recommendations5 = response.jsonPath().getMap("recommendation[5]");

System.out.print("\n\n");
System.out.print(recommendations5.get("validatingAirlineName"));
System.out.print("\n\n");
System.out.println("adultBaseFare=" + recommendations5.get("adultBaseFare"));
System.out.println("adultTaxFare=" + recommendations5.get("adultTaxFare"));
System.out.println("Deeplink=" + recommendations5.get("Deeplink"));
System.out.println("marketingAirlineCodes=" + recommendations5.get("marketingAirlineCodes"));
System.out.println("validatingAirlineName=" + recommendations5.get("validatingAirlineName"));
System.out.println("totalBaseFare=" + recommendations5.get("totalBaseFare"));
System.out.println("totalFare=" + recommendations5.get("totalFare"));
System.out.println("validatingAirlineCode=" + recommendations5.get("validatingAirlineCode"));
System.out.println("validatingAirlineName=" + recommendations5.get("validatingAirlineName"));

下面是my循环逻辑，但失败了。

我的错误：

线程"main“中的

异常java.lang.IllegalArgumentException:使用了参数"i”，但没有定义参数。使用JsonPath.params(.)定义参数函数

我的for循环代码：

for(int i=0;i<=jsonResponse.size();i++)
{
    Map<String, String> recommendations5 = response.jsonPath().getMap("recommendation[i]");
    System.out.print("\n\n");
    System.out.print(recommendations5.get("validatingAirlineName"));
    System.out.print("\n\n");
    System.out.println("adultBaseFare=" + recommendations5.get("adultBaseFare"));
    System.out.println("adultTaxFare=" + recommendations5.get("adultTaxFare"));
    System.out.println("Deeplink=" + recommendations5.get("Deeplink"));
    System.out.println("marketingAirlineCodes=" + recommendations5.get("marketingAirlineCodes"));
    System.out.println("validatingAirlineName=" + recommendations5.get("validatingAirlineName"));
    System.out.println("totalBaseFare=" + recommendations5.get("totalBaseFare"));
    System.out.println("totalFare=" + recommendations5.get("totalFare"));
    System.out.println("validatingAirlineCode=" + recommendations5.get("validatingAirlineCode"));
    System.out.println("validatingAirlineName=" + recommendations5.get("validatingAirlineName"));
}

Answer 1

您需要替换字符串i将实际的i int值

Map<String, String> recommendations5 = response.jsonPath().getMap("recommendation[" + i + "]");