颤振未来返回未来的实例

Question

我正在进行api调用以接收数据。当我打电话的时候，我得到了未来的一个例子。为什么这仍然返回一个未来的实例，而不是等待数据？

这是我的网络文件

class NetworkHelper {
  NetworkHelper(this.url);

  final String url;

Future getSecureData(String token) async {
    http.Response response = await http.post(
      Uri.parse(url),
      headers: {
        HttpHeaders.authorizationHeader: token,
      },
    );
    var data = response;
    return data;
  }

这是我的帐户设置文件

class AccountSettings extends StatefulWidget {
  const AccountSettings({Key? key}) : super(key: key);
  static const String id = 'account_settings';

  @override
  State<AccountSettings> createState() => _AccountSettingsState();
}

class _AccountSettingsState extends State<AccountSettings> {
  var userData;

  @override
  void initState() {
    super.initState();

    getUserData();
  }

  Future getUserData() async {
    var token = await SecureStorage.getAccessToken();
    var jwttoken = 'JWT ' + token!;
    NetworkHelper networkHelper =
        NetworkHelper('http://localhost:8000/auth/users/me');
    userData = await networkHelper.getSecureData(jwttoken);
  }

  @override
  Widget build(BuildContext context) {
    print(userData);
    return Scaffold(

Answer 1

Future getSecureData(String token) async {
    http.Response response = await http.post(
      Uri.parse(url),
      headers: {
        HttpHeaders.authorizationHeader: token,
      },
    );
    var data = response; // This might be off.
    var data = jsonDecode(response.body) // Try replacing with this.
    return data;
  }