在python中将矩阵转换为梯级形式

Question

from sympy import *

matrix = []
print("Enter the entries of the 3x3 matrix:")

for i in range(0,3):
    a =[]
    for j in range(0,3):
         a.append(int(input()))
    matrix.append(a)

for i in range(0,3):
    for j in range(0,3):
        print(matrix[i][j], end = " ")
    print()
    
for i in range(0,3):
    for j in range(0,3):
        M[i][j]=list(matrix[i][j])

M_rref = M.rref()
print("The Row echelon form of matrix M and the pivot columns : {}".format(M_rref))

当我将数组相互传输时，出现了一个错误。我只想把3x3矩阵转换成梯队。TypeError：'int‘对象不可迭代，有时AttributeError：'list’对象没有属性'rref‘

Answer 1

只需将matrix转换为SymPy Matrix，如下所示：

from sympy import *

matrix = []
print("Enter the entries of the 3x3 matrix:")

for i in range(0,3):
    a =[]
    for j in range(0,3):
         a.append(int(input()))
    matrix.append(a)

for i in range(0,3):
    print(matrix[i])

M = Matrix(matrix)
M_rref = M.rref()
print("The Row echelon form of matrix M and the pivot columns : {}".format(M_rref))