将对象转换为数组

Question

我有一个包含其他对象的对象，以及一些我不想要的数字。

我希望将对象转换为对象数组并删除数字。

举个例子：

输入

const object = {

  john: {
    instrument: 'violin',
    age: 26
  },

  bob: {
    instrument: 'guitar',
    age: 32
  },

  numberIDontWant: 2,

  flynn: {
    instrument: 'piano',
    age: 3
  },

  numberIDontWant2: 9
}

输出

  [
    {
      name: 'john',
      instrument: 'violin',
      age: 26
    },
    {
      name: 'bob',
      instrument: 'guitar',
      age: 32
    },
    {
      name: 'flynn',
      instrument: 'piano',
      age: 20
    }
  ]

有人能帮我吗？

Answer 1

你可以用Object.entries和.map

​

console.log(Object.entries({
  john: {
    instrument: 'violin',
    age: 26
  },

  bob: {
    instrument: 'guitar',
    age: 32
  },

  numberIDontWant: 2,

  flynn: {
    instrument: 'piano',
    age: 3
  },

  numberIDontWant2: 9
}).map(([k,v]) => typeof v === 'object' ? ({...v, name: k}) : undefined).filter(i => i))

​

Answer 2

您很可能希望在Object.entries()上迭代，这样您就可以访问键( name)和值。并不是100%清楚什么是包含/排除哪些值的标准，但一种方法是只包含typeof等于'object'的值。

​

function objectToArray(obj) {
    let arr = [];
    for (let [name, value] of Object.entries(obj)) {
        if (typeof value === "object") {
            arr.push({
                ...value,
                name,
            });
        }
    }

    return arr;
}

console.log(
    objectToArray({
        john: {
            instrument: "violin",
            age: 26,
        },

        bob: {
            instrument: "guitar",
            age: 32,
        },

        numberIDontWant: 2,

        flynn: {
            instrument: "piano",
            age: 3,
        },

        numberIDontWant2: 9,
    })
);

​

Answer 3

你可以用map和filter

​

const data = {
  john: {
    instrument: 'violin',
    age: 26
  },
  bob: {
    instrument: 'guitar',
    age: 32
  },
  numberIDontWant: 2,
  flynn: {
    instrument: 'piano',
    age: 3
  },
  numberIDontWant2: 9
}

const result = Object.entries(data).map(([k, v]) => {
    if (typeof v === "object") return { ...v, name: k }
}).filter(x => x);

console.log(result);

​