如何将对象输送到apply调用中的特定位置,这不是第一个输入?magrittr点占位符似乎不适用于此。
dat <- 1:10
locs <- list(c(1, 2),
c(3, 4),
c(5, 6))
foo <- function(x, y, z) {
out <- mean(c(x[y], x[z]))
return(out)
}
# works
lapply(locs, function(z) foo(dat, z[1], z[2]))
# none of these work
dat %>%
lapply(locs, function(z) foo(., z[1], z[2]))
dat %>%
lapply(locs, function(z) foo((.), z[1], z[2]))
dat %>%
lapply(locs, function(z) {. %>% foo(z[1], z[2])})
# New native pipe and placeholder also do not work
dat |>
lapply(locs, function(z) foo(_, z[1], z[2])) 发布于 2022-05-18 11:23:04
您可以像下面这样使用{}
> dat %>%
+ {lapply(locs, function(z) foo(., z[1], z[2]))}
[[1]]
[1] 1.5
[[2]]
[1] 3.5
[[3]]
[1] 5.5https://stackoverflow.com/questions/72288169
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