如何过滤python中的.json数组，使每个元素中只有一个参数显示？

Question

就像标题说的那样，我在过滤来自CoinGecko API的数组时遇到了问题。数组如下所示：

[
  {
    "id": "01coin",
    "symbol": "zoc",
    "name": "01coin"
  },
  {
    "id": "0-5x-long-algorand-token",
    "symbol": "algohalf",
    "name": "0.5X Long Algorand Token"
  },
  {
    "id": "0-5x-long-altcoin-index-token",
    "symbol": "althalf",
    "name": "0.5X Long Altcoin Index Token"
  }
]

在过滤器之后，我希望它只显示如下“id”：

[
  "01coin",
  "0-5x-long-algorand-token",
  "0-5x-long-altcoin-index-token"
]

我就是这样过滤它的：

coinList = 'https://api.coingecko.com/api/v3/coins/list'
listCall = requests.get(coinList)
jsonCall = json.loads(listCall.content)
coinIds = [x for x in jsonCall if x == 'id']

Answer 1

您的列表理解是有某种意义的，但是您应该在每个字典中索引，而不是使用一个if子句。看起来应该是：

[item["id"] for item in jsonCall]

这一产出如下：

['01coin', '0-5x-long-algorand-token', '0-5x-long-altcoin-index-token']