我有一个具有值的Laravel集合,我想按“类型”进行分组,并按最大的“概率”排序。以下是我的收藏的样子:
Illuminate\Support\Collection Object
(
[items:protected] => Array
(
[0] => Array
(
[type] => correct-score
[name] => 1-1
[probability] => 10.599257670442
[probability_odd] => 10.142219704667
[odd] =>
[value_bet] => 0
[prognose_type_id] => 12
[value_bet_diff] => -10.142219704667
)
[1] => Array
(
[type] => 3-way
[name] => 1
[probability] => 52.459602877727
[probability_odd] => 2.0491958402842
[prognose_type_id] => 1
[odd] => 2.48
[value_bet_diff] => 0.4308041597158
)
[2] => Array
(
[type] => 3-way
[name] => 2
[probability] => 24.682032371379
[probability_odd] => 4.3553949845985
[prognose_type_id] => 1
[odd] => 2.66
[value_bet_diff] => -1.6953949845985
)
[3] => Array
(
[type] => 3-way
[name] => X
[probability] => 22.857984044926
[probability_odd] => 4.7029519221256
[prognose_type_id] => 1
[odd] => 3.7
[value_bet_diff] => -1.0029519221256
)
[4] => Array
(
[type] => double-chance
[name] => 1X
[probability] => 37.658793461327
[probability_odd] => 2.8545789739758
[prognose_type_id] => 4
[odd] => 1.49
[value_bet_diff] => -1.3645789739758
)
[5] => Array
(
[type] => double-chance
[name] => X2
[probability] => 23.770008208152
[probability_odd] => 4.5225058005294
[prognose_type_id] => 4
[odd] => 1.55
[value_bet_diff] => -2.9725058005294
)
[6] => Array
(
[type] => double-chance
[name] => 12
[probability] => 38.570817624553
[probability_odd] => 2.7870811826288
[prognose_type_id] => 4
[odd] => 1.29
[value_bet_diff] => -1.4970811826288
)
[7] => Array
(
[type] => both-to-score
[name] => yes
[probability] => 58.505776168275
[probability_odd] => 1.8374254140447
[prognose_type_id] => 8
[odd] =>
[value_bet_diff] => -1.8374254140447
)因此,我想实现这样的目标:
Illuminate\Support\Collection Object
(
[items:protected] => Array
(
[0] => Array
(
[type] => correct-score
[name] => 1-1
[probability] => 10.599257670442
[probability_odd] => 10.142219704667
[odd] =>
[value_bet] => 0
[prognose_type_id] => 12
[value_bet_diff] => -10.142219704667
)
[1] => Array
(
[type] => 3-way
[name] => 1
[probability] => 52.459602877727
[probability_odd] => 2.0491958402842
[prognose_type_id] => 1
[odd] => 2.48
[value_bet_diff] => 0.4308041597158
)
[6] => Array
(
[type] => double-chance
[name] => 12
[probability] => 38.570817624553
[probability_odd] => 2.7870811826288
[prognose_type_id] => 4
[odd] => 1.29
[value_bet_diff] => -1.4970811826288
)
[7] => Array
(
[type] => both-to-score
[name] => yes
[probability] => 58.505776168275
[probability_odd] => 1.8374254140447
[prognose_type_id] => 8
[odd] =>
[value_bet_diff] => -1.8374254140447
)还没有找到类似的解决方案,所以我最终决定在这里尝试。你能帮帮我吗?
提前感谢!
发布于 2022-05-08 20:08:24
也许最好以雄辩的口才来做这件事,但就像你把它当作一个集合问题一样;
假设您的集合名为$items
$sorted = $items->groupBy('type')
->map(function($group){
return $group->sortByDesc('probability')->take(1);
})
->flatten(1);发布于 2022-05-08 20:55:24
最简短的:
$items = $collections
->sortByDesc('probability')
->unique('type');https://stackoverflow.com/questions/72163972
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