我从Json中的API调用接收Lats & Longs的String。
"lineStrings": [
"[[[-0.301457,51.515017],[-0.288265,51.51014],[-0.280462,51.503057],[-0.267972,51.494627],[-0.254555,51.495148],[-0.245704,51.494917],[-0.235881,51.494122],[-0.22362,51.4923],[-0.213427,51.490311],[-0.206636,51.490459],[-0.193378,51.492063],[-0.182658,51.494316],[-0.174138,51.494094],[-0.156377,51.49227],[-0.143102,51.496359],[-0.133608,51.499544],[-0.124861,51.50132],[-0.122666,51.507058],[-0.11426,51.511006],[-0.103659,51.511581],[-0.094009,51.512117],[-0.090432,51.51151],[-0.085969,51.5107],[-0.076546,51.509971],[-0.072384,51.515037],[-0.059971,51.519518],[-0.046596,51.521858],[-0.03364,51.525122],[-0.025128,51.52694],[-0.011538,51.524839],[0.005055,51.528136],[0.017451,51.531341],[0.035263,51.53534],[0.051186,51.538948],[0.081053,51.539321],[0.10153,51.538372],[0.127016,51.540331],[0.147527,51.541639],[0.166017,51.544096],[0.19864,51.549775],[0.219116,51.554093],[0.235809,51.55856],[0.250882,51.559063]]]"]与我习惯的调用不同,它们不是我可以迭代的单个lat和long值,它作为一个长字符串块返回。
我可能不正确,但我不相信我能够解析它,因为没有lat & long类可以迭代,只有lineStrings,这是一个很长的块。我要解析的Quicktype.io类在迭代时带我到.linestrings
我想把它们分割成坐标对,这样我就可以从每个坐标中取lat & long。
我试过‘拆分’,但是由于双打之间的逗号,我无法让它工作。我也尝试删除特殊字符,但无法保持格式化。
欢迎任何建议。
最终目标是能够执行以下操作
for (var x in coordinates){
GeoCoordinates y = GeoCoordinates(x.latitude, x.longitude);
}谢谢
发布于 2022-05-06 14:15:02
您必须手动拆分:
void main() {
'[[[-0.301457,51.515017],[-0.288265,51.51014],[-0.280462,51.503057]]]'
.split('],[')
.forEach((p) => print(p.replaceAll('[', '').replaceAll(']', '')));
}指纹:
-0.301457,51.515017
-0.288265,51.51014
-0.280462,51.503057您可以在,上进一步拆分,并将其解析为一对双倍。
或者您可以添加一个LatLong类来保存这一对:
void main() {
final latLongs =
'[[[-0.301457,51.515017],[-0.288265,51.51014],[-0.280462,51.503057]]]'
.split('],[')
.map((p) => LatLong.fromString(
p.replaceAll('[', '').replaceAll(']', ''),
));
print(latLongs);
}
class LatLong {
LatLong(this.lat, this.long);
factory LatLong.fromString(String pair) {
final parts = pair.split(',');
return LatLong(double.parse(parts[0]), double.parse(parts[1]));
}
double lat;
double long;
}发布于 2022-05-06 14:26:49
var json = {"lineStrings": [
"[[[-0.301457,51.515017],[-0.288265,51.51014],[-0.280462,51.503057],[-0.267972,51.494627],[-0.254555,51.495148],[-0.245704,51.494917],[-0.235881,51.494122],[-0.22362,51.4923],[-0.213427,51.490311],[-0.206636,51.490459],[-0.193378,51.492063],[-0.182658,51.494316],[-0.174138,51.494094],[-0.156377,51.49227],[-0.143102,51.496359],[-0.133608,51.499544],[-0.124861,51.50132],[-0.122666,51.507058],[-0.11426,51.511006],[-0.103659,51.511581],[-0.094009,51.512117],[-0.090432,51.51151],[-0.085969,51.5107],[-0.076546,51.509971],[-0.072384,51.515037],[-0.059971,51.519518],[-0.046596,51.521858],[-0.03364,51.525122],[-0.025128,51.52694],[-0.011538,51.524839],[0.005055,51.528136],[0.017451,51.531341],[0.035263,51.53534],[0.051186,51.538948],[0.081053,51.539321],[0.10153,51.538372],[0.127016,51.540331],[0.147527,51.541639],[0.166017,51.544096],[0.19864,51.549775],[0.219116,51.554093],[0.235809,51.55856],[0.250882,51.559063]]]"
]
};
List<dynamic> jsonList = json["lineStrings"]!
.first
.replaceAll("[", "")
.replaceAll("]", "")
.split(",");
List<Coordinates> result = [];
for (var i = 0; i < jsonList.length / 2; i++) {
result.add(Coordinates(
lat: double.parse(jsonList[i]),
long: double.parse(jsonList[i + 1])));
}
result.forEach((element) {
print("Lat" + element.lat.toString());
print("Long" + element.long.toString());
print("*************************");
});
class Coordinates {
double lat;
double long;
Coordinates({
required this.lat,
required this.long,
});
}颤振: Lat-0.301457
颤振: Long51.515017
颤振:*
颤振: Lat51.515017
颤振:长-0.288265
颤振:*
颤振: Lat-0.288265
颤振: Long51.51014
颤振:*
https://stackoverflow.com/questions/72142514
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