我什么都试过了有人能帮我吗?I‘s有3个错误:foreach().
PHP: 8.0 MYSQL: 5.1
foreach($_FILES["userfile"]["tmp_name"] as $key=>$tmp_name) {
$file_name=$_FILES["userfile"]["name"][$key];
$pasta_dir = "../www/layout/diario_de_obra/upload_img/";
$diretorio_img = $pasta_dir . $file_name;
$arquivo = $_FILES["userfile"]['tmp_name'][$key];
move_uploaded_file($arquivo, $diretorio_img);
print($file_name." enviado com sucesso!");
}
<div enctype="multipart/form-data"> <!-- action="upload" method="post" accept=”image/* class="simagem" -->
<label>Selecione as fotos de hoje aqui:
<input id="image-file" type="file" name="userfile[]">
<input id="image-file" type="file" name="userfile[]">
</label>
</div>
发布于 2022-04-29 15:39:00
在玩了你的例子之后,我想出了这个
<form action="imageUpload.php" method="post" enctype="multipart/form-data">
<div> <!-- action="upload" method="post" accept=”image/* class="simagem" -->
<label>Selecione as fotos de hoje aqui:
<input id="image-file" type="file" name="userfile[]">
<input id="image-file" type="file" name="userfile[]">
</label>
</div>
<button type="submit">click me</button>
</form>现在您的PHP开始工作了。
https://stackoverflow.com/questions/72059695
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