我正在尝试通过swizzling iOS构造函数方法向UIColor添加一种形式的主题支持。当控件使用“命名颜色”(手动添加到资产目录中的颜色)时,我遇到了来自情节提要的场景的问题。在将堆栈跟踪打印到我所使用的UIColor(named: ....)构造函数之前,它会调用UIColor initWithCoder。我想,如果我能用它来代替,提取在故事板中输入的“名称”,它将解决我的问题。(我知道这个值将在另一个构造函数中传递,但我需要看看它是否可能来自编码器构造函数,长话短说)
我很难理解如何从NSCoder中获取这个值。我找不到关于它的底层UINibDecoder类型的任何信息,调试器没有提供任何有用的信息,我不知道对象使用什么键/类型,所以我不能调用coder.decode...函数,我也找不到任何关于如何打印所有键/类型的在线信息。如有任何见解/帮助,将不胜感激
我目前拥有的代码大致如下:
extension UIColor {
private static let originalCoderSelector = #selector(UIColor.init(coder:))
private static let swizzledCoderSelector = #selector(theme_color(withCoder:))
class func swizzleNamedColorInitToAddTheme() {
guard let originalCoderMethod = class_getInstanceMethod(self, originalCoderSelector),
let swizzledCoderMethod = class_getInstanceMethod(self, swizzledCoderSelector) else {
os_log("Unable to find UIColor methods to swizzle", log: .default, type: .error)
return
}
method_exchangeImplementations(originalCoderMethod, swizzledCoderMethod);
}
@objc func theme_color(withCoder coder: NSCoder) -> UIColor? {
print("coder being called")
print("coder test: \( coder.decodeObject(forKey: "backgroundColor") ) ")
print("coder test: \( coder.decodeObject(forKey: "color") ) ")
print("coder test: \( coder.decodeObject(forKey: "name") ) ")
print("coder test: \( coder.decodeObject(forKey: "namedColor") ) ")
print("coder test: \( coder.decodePropertyList(forKey: "backgroundColor") ) ")
print("coder test: \( coder.decodePropertyList(forKey: "color") ) ")
print("coder test: \( coder.decodePropertyList(forKey: "name") ) ")
print("coder test: \( coder.decodePropertyList(forKey: "namedColor") ) ")
return nil
}
}发布于 2022-04-23 09:12:06
利用this answer中的这种技术,我们可以通过对NSKeyedUnarchiver.decodeObject(forKey:)进行切换来获得编码密钥。
extension NSKeyedUnarchiver {
private static let originalDecodeObject = #selector(NSKeyedUnarchiver.decodeObject(forKey:))
private static let swizzledDecodeObject = #selector(swizzledDecodeObject)
@objc
func swizzledDecodeObject(forKey key: String) -> Any? {
print("Key:", key)
return swizzledDecodeObject(forKey: key)
}
class func swizzle() {
if let orig = class_getInstanceMethod(self, originalDecodeObject),
let new = class_getInstanceMethod(self, swizzledDecodeObject) {
method_exchangeImplementations(orig, new)
}
}
}然后,您可以对颜色进行编码和解码,以查看哪些键被解码:
let data = try! NSKeyedArchiver.archivedData(withRootObject: UIColor(named: "foo"), requiringSecureCoding: false)
let decoded = try! NSKeyedUnarchiver.unarchivedObject(ofClass: UIColor.self, from: data)在iOS 15.0上,这是我在资产目录中添加的颜色的打印:
Key: root
Key: UIDynamicModifiedBaseColor
Key: UIDynamicCatalogName
Key: UIDynamicCatalogBundleIdentifier
Key: UIDynamicCatalogBundleLibraryName从列表中可以看出,使用一些常识,UIDynamicCatalogName似乎是您要寻找的关键。
请注意,这将不适用于基色如systemRed,或系统颜色如systemBackground。对于后者,您应该使用键UISystemColorName (您可以通过编码和解码.systembackground找到这一点)。对于前者,还不清楚用什么键来编码它。通过编码和解码.systemYellow,我们可以看到与.systembackground相同的密钥,但使用UISystemColorName似乎不起作用。可能是不同的编码方式..。
https://stackoverflow.com/questions/71972024
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