TypeError：“int”类型的参数在不正确的语音识别时不可迭代

Question

我正在为一个学校项目开发一个TTS/STT系统，它一直进行得很好，直到当代码经过"Google语音识别不承认您所说的话“时，我才开始得到这个特定的错误。我不知道为什么我会犯这个错误。我正在使用的python库只是python、语音识别和py音频库。我的密码在下面。

from subprocess import call
import speech_recognition as sr
import serial
r = sr.Recognizer()
import os,time
def listen1():
    with sr.Microphone(device_index = 2) as source:
            r.adjust_for_ambient_noise(source)
            print("Please speak.");
            audio = r.listen(source)
            print("Heard.");
    return audio
def voice(audio1):
    try:
        text1 = r.recognize_google(audio1)
        ##call('espeak ' +text, shell=True)
        print("You said: " +text1);
        return text1;
    except sr.UnknownValueError:
        call(["espeak", "-a 200 -v en+1 ", "Google Speech Recognition did not recognize what you said."])
        print("Google Speech Recognition did not recognize what you said.")
        return 0
    except sr.RequestError as e:
        print("Could not request results fromm Google")
        return 0
def main(text):
    audio1 = listen1()
    text = voice(audio1)  
    if 'hello' in text:
        call(["espeak", "-a 200 -v en+1" , "Hi, how are you"])
    if 'good' in text:
        call(["espeak", "-a 200 -v en+1" , "Good to hear, now what will you have me do?"])
    if 'exit' in text:
        call(["espeak", "-a 200 -v en+1" , "Thank you, exiting."])
        exit()
    text = {}
    main(text)
if __name__ =='__main__':
 while(1):
    audio1=listen1()
    text = voice(audio1)
    if text == 'start':
        text = {}
        call(["espeak", "-a 200 -v en+1" ,"Hello, user, please say a commmand"])
        main(text)
    else:
        call(["espeak", "-a 200 -v en+1 " ,"Did not recognize command, repeat please?"])

我能做些什么来纠正这个错误？谢谢!

Answer 1

正如注释中提到的，当您得到错误时，函数voice()将0返回到main()中的变量文本。该函数用于if 'hello' in text:。但是您不能在0上进行一个in测试，因为它是一个整数。