提取URL "/“中特定字符串之间的文本

Question

我试图在一组特定的字符之前收集所有的东西

也就是说，我有一个URL，如下所示

url = "https://www.somewebsiteLink.com/someDirectory/Directory/ascensor/163235494/d"

url2 = "https://www.somewebsiteLink.com/someDirectory/Directory/aire-acondicionado-calefaccion-ascensor/45837493/d

我想从链接中提取两件事：

链接1：ascensor和163235494链接2：aire-acondicionado-calefaccion-ascensor和45837493

最后一个/之间的数字，最后一个/之间的文本。

Answer 1

将/上的字符串拆分，并将第3和第2到最后的元素拉出：

url = "https://www.somewebsiteLink.com/someDirectory/Directory/ascensor/163235494/d"
url2 = "https://www.somewebsiteLink.com/someDirectory/Directory/aire-acondicionado-calefaccion-ascensor/45837493/d"
urls = c(url, url2)

pieces = strsplit(urls, split = "/")
result = lapply(pieces, \(x) x[length(x) - 2:1])
## for older R verions:
# result = lapply(pieces, function(x) x[length(x) - 2:1])

result                
# [[1]]
# [1] "ascensor"  "163235494"
# 
# [[2]]
# [1] "aire-acondicionado-calefaccion-ascensor" "45837493"