Scrypto交易清单从帐户多次转账

Question

我们如何从一个清单中的一个帐户进行多个令牌传输？例如：

帐户A --令牌A->帐户B

帐户A --令牌B->帐户B

帐户A --令牌A->帐户C

帐户A-令牌B->帐户C

我做了这个：

CLONE_BUCKET_REF BucketRef(1u32) BucketRef("badge1");
CALL_METHOD Address("0293c502780e23621475989d707cd8128e4506362e5fed6ac0c00a") "withdraw" Decimal("2000") Address("03bcc1960b6f99bae8614c3bf276ee3217f800f5cc7bdc48db9a5f") BucketRef("badge1");

CALL_METHOD_WITH_ALL_RESOURCES Address("02a2a79aa613da237bcda37fd79af36e09eadd195976092cb24696") "deposit_batch";

CLONE_BUCKET_REF BucketRef(1u32) BucketRef("badge2");
CALL_METHOD Address("0293c502780e23621475989d707cd8128e4506362e5fed6ac0c00a") "withdraw" Decimal("2000") Address("031773788de8e4d2947d6592605302d4820ad060ceab06eb2d4711") BucketRef("badge2");

CALL_METHOD_WITH_ALL_RESOURCES Address("02a2a79aa613da237bcda37fd79af36e09eadd195976092cb24696") "deposit_batch";

CLONE_BUCKET_REF BucketRef(1u32) BucketRef("badge3");
CALL_METHOD Address("0293c502780e23621475989d707cd8128e4506362e5fed6ac0c00a") "withdraw" Decimal("2000") Address("03bcc1960b6f99bae8614c3bf276ee3217f800f5cc7bdc48db9a5f") BucketRef("badge3");
CALL_METHOD_WITH_ALL_RESOURCES Address("0236ca00316c8eb5ad51b0cb5e3f232cb871803a85ec3847b36bb4") "deposit_batch";

CLONE_BUCKET_REF BucketRef(1u32) BucketRef("badge4");
CALL_METHOD Address("0293c502780e23621475989d707cd8128e4506362e5fed6ac0c00a") "withdraw" Decimal("2000") Address("031773788de8e4d2947d6592605302d4820ad060ceab06eb2d4711") BucketRef("badge4");

CALL_METHOD_WITH_ALL_RESOURCES Address("0236ca00316c8eb5ad51b0cb5e3f232cb871803a85ec3847b36bb4") "deposit_batch";

但我知道这个错误：

Error: CompileError(GeneratorError(IdValidatorError(BucketRefNotFound(Rid(1)))))

当我们调用CALL_METHOD_WITH_ALL_RESOURCES时，我们似乎失去了对一个帐户的所有引用

Answer 1

您确实是正确的，CALL_METHOD_WITH_ALL_RESOURCES指令删除事务中的所有BucketRef。发生这种情况的具体行是：https://github.com/radixdlt/radixdlt-scrypto/blob/7cb4af0b35b8462f214e839590234602a11281d0/radix-engine/src/engine/process.rs#L367

解决这个问题的方法之一是避免在CALL_METHOD_WITH_ALL_RESOURCES文件结束之前使用rtm，而是将rtm文件中的CALL_METHOD_WITH_ALL_RESOURCES替换为TAKE_ALL_FROM_WORKTOP和常规的deposit方法调用。

因此，作为一个高层次的观点，我们试图做的每一个转移是: 1-克隆徽章。2-使用克隆徽章收回代币。3-从撤回的令牌中创建一个桶。4-把我们刚创建的水桶存入接收者的账户。

我对您的rtm文件做了上述修改：

CLONE_BUCKET_REF BucketRef(1u32) BucketRef("badge1");
CALL_METHOD Address("0293c502780e23621475989d707cd8128e4506362e5fed6ac0c00a") "withdraw" Decimal("2000") Address("03bcc1960b6f99bae8614c3bf276ee3217f800f5cc7bdc48db9a5f") BucketRef("badge1");
TAKE_ALL_FROM_WORKTOP Address("03bcc1960b6f99bae8614c3bf276ee3217f800f5cc7bdc48db9a5f") Bucket("transfer1_bucket");
CALL_METHOD Address("02a2a79aa613da237bcda37fd79af36e09eadd195976092cb24696") "deposit" Bucket("transfer1_bucket");

CLONE_BUCKET_REF BucketRef(1u32) BucketRef("badge2");
CALL_METHOD Address("0293c502780e23621475989d707cd8128e4506362e5fed6ac0c00a") "withdraw" Decimal("2000") Address("031773788de8e4d2947d6592605302d4820ad060ceab06eb2d4711") BucketRef("badge2");
TAKE_ALL_FROM_WORKTOP Address("031773788de8e4d2947d6592605302d4820ad060ceab06eb2d4711") Bucket("transfer2_bucket");
CALL_METHOD Address("02a2a79aa613da237bcda37fd79af36e09eadd195976092cb24696") "deposit" Bucket("transfer2_bucket");

CLONE_BUCKET_REF BucketRef(1u32) BucketRef("badge3");
CALL_METHOD Address("0293c502780e23621475989d707cd8128e4506362e5fed6ac0c00a") "withdraw" Decimal("2000") Address("03bcc1960b6f99bae8614c3bf276ee3217f800f5cc7bdc48db9a5f") BucketRef("badge3");
TAKE_ALL_FROM_WORKTOP Address("03bcc1960b6f99bae8614c3bf276ee3217f800f5cc7bdc48db9a5f") Bucket("transfer3_bucket");
CALL_METHOD Address("0236ca00316c8eb5ad51b0cb5e3f232cb871803a85ec3847b36bb4") "deposit" Bucket("transfer3_bucket");

CLONE_BUCKET_REF BucketRef(1u32) BucketRef("badge4");
CALL_METHOD Address("0293c502780e23621475989d707cd8128e4506362e5fed6ac0c00a") "withdraw" Decimal("2000") Address("031773788de8e4d2947d6592605302d4820ad060ceab06eb2d4711") BucketRef("badge4");
TAKE_ALL_FROM_WORKTOP Address("031773788de8e4d2947d6592605302d4820ad060ceab06eb2d4711") Bucket("transfer4_bucket");
CALL_METHOD Address("0236ca00316c8eb5ad51b0cb5e3f232cb871803a85ec3847b36bb4") "deposit" Bucket("transfer4_bucket");

编辑：，我只想强调这个答案是针对Scryptov0.3.0的。