正则表达式仅在前面的所有行都有关键字时才捕获。

Question

我希望有一个正则表达式，只有在前面的行都以关键字'PASS‘开头时，它才能与CLPM_FPGA_xx ID匹配

如果前面的任何一行以单词“FAIL”开头，则不应提取CLPM_FPGA_xx ID

我认为这比较容易，但由于前面的行数是可变的，失败行可能是第一、最后或中间的，所以我一直在挣扎

如有任何建议请见谅。

==示例数据========

通过:锁相环锁定信号在复位状态为0。

通过:锁相环锁定信号状态为1。

传球:锁相环锁定在预期时间内: 5000000 ps。

需求验证: CLPM_FPGA_31

关卡:系统时钟高峰周期为8000 ps。

失败:系统时钟低周期是8000 ps。

关卡:系统时钟周期为16000 ps。

需求验证: CLPM_FPGA_32

通行证:系统时钟到国际金融公司的延迟是10 ps。

需求验证: CLPM_FPGA_31

通行证:系统时钟到国际金融公司的延迟是10 ps。

需求验证: CLPM_FPGA_34

失败:系统时钟低周期是8000 ps。

关卡:系统时钟高峰周期为8000 ps。

关卡:系统时钟周期为16000 ps。

需求验证: CLPM_FPGA_32

关卡:系统时钟高峰周期为8000 ps。

关卡:系统时钟周期为16000 ps。

失败:系统时钟低周期是8000 ps。

需求验证: CLPM_FPGA_32

失败:系统时钟低周期是8000 ps。

需求验证: CLPM_FPGA_33

=====================================

Reg Exp尝试：

^(?!(FAIL:|Requirements)).(\n^PASS:.)+\nRequirements验证：\t+(CLPM_FPGA_.*)

但是，这与在失败后立即发生传球的情况相匹配。

Answer 1

其思想是在块上拆分文本，过滤出具有“失败”状态的块，然后找到id。

注意:为了更好地控制匹配，我将ids替换为非重复编号(从31到37)。

可能的解决办法如下：

import re

string = """PASS: PLL Lock signal state at reset is 0.
PASS: PLL Lock signal state is 1.
PASS: PLL Locked within expected time: 5000000 ps.
Requirements verified: CLPM_FPGA_31

PASS: System Clock high period is 8000 ps.
FAIL: System Clock low period is 8000 ps.
PASS: System Clock period is 16000 ps.
Requirements verified: CLPM_FPGA_32

PASS: System Clock to IFC delay is 10 ps.
Requirements verified: CLPM_FPGA_33

PASS: System Clock to IFC delay is 10 ps.
Requirements verified: CLPM_FPGA_34

FAIL: System Clock low period is 8000 ps.
PASS: System Clock high period is 8000 ps.
PASS: System Clock period is 16000 ps.
Requirements verified: CLPM_FPGA_35

PASS: System Clock high period is 8000 ps.
PASS: System Clock period is 16000 ps.
FAIL: System Clock low period is 8000 ps.
Requirements verified: CLPM_FPGA_36

FAIL: System Clock low period is 8000 ps.
Requirements verified: CLPM_FPGA_37"""

string_blocks = string.split("\n\n")


re_pattern = re.compile(r"PASS.+\n.+CLPM_FPGA_(\d+)$", re.M)

result = []

for string_block in string_blocks:
    if 'FAIL' not in string_block:
        found = re_pattern.findall(string_block)
        result.extend(found)

print(result)

指纹：

['31', '33', '34']