如何在discord.spotify中使用discord.py类

Question

discord.py文档有一个spotify类(https://discordpy.readthedocs.io/en/stable/api.html#spotify)，我想知道如何将此活动设置为概要文件。文档中没有示例。我尝试在on_ready事件中使用此活动。

@client.event
async def on_ready():
  print("Bot was connected to the server")
  
  await bot.change_presence(activity=discord.Spotify(title = "Test"))

我的输出是错的。

Bot was connected to the server

Ignoring exception in on_ready
Traceback (most recent call last):
  File "/home/runner/Russian-field-of-experiments-on-the-island-of-Python/venv/lib/python3.8/site-packages/discord/client.py", line 343, in _run_event
    await coro(*args, **kwargs)
  File "main.py", line 13, in on_ready
    await bot.change_presence(activity=discord.Spotify(title = "Test"))
  File "/home/runner/Russian-field-of-experiments-on-the-island-of-Python/venv/lib/python3.8/site-packages/discord/activity.py", line 527, in __init__
    self._sync_id = data.pop('sync_id')
KeyError: 'sync_id'

完整源代码：

import discord
from discord.ext import commands

bot = commands.Bot(command_prefix="!")

@bot.event
async def on_ready():
  print("Bot was connected to the server")

 await bot.change_presence(activity=discord.Spotify(title = "Test"))

bot.run("token")

如何在discord.py中使用Spotify类？

Answer 1

要将机器人的状态更改为"listening to Spotify"，可以这样做：

await bot.change_presence(activity=discord.Activity(type=discord.ActivityType.listening, name="Spotify"))

如果要将其设置为特定用户正在侦听的内容，可以这样做：

from discord import Spotify

@bot.event
async def on_ready():
user = bot.get_user(user_id) # Make sure to change this to the users ID.
while True:
 for activity in user.activities:
        if isinstance(activity, Spotify):
           await bot.change_presence(activity=discord.Activity(type=discord.ActivityType.listening, name=f"{activity.title} by {activity.artist}"))
        else:
             await bot.change_presence(activity=discord.Activity(type=discord.ActivityType.listening, name=f"Nothing")) # User isn't listening to Spotify

要使上述操作正常运行，您定义的用户必须侦听Spotify。如果他们不收听Spotify，则状态将更改为Nothing。