Discord.JS获取附件URL并发送通道

Question

我有这个机器人代码"discord.js v13"，我需要获得附加文件的网址并立即发送链接。我该怎么做？我将把代码部分留在下面

            // save file in folder 'musicas'
            stream.pipe(createWriteStream(__dirname + `/musicas/${pegaid}.mp3`)).on('finish', () => {

                // Sending the attachment, and its link
                try {
                    message.channel.send({
                        files: [{
                            attachment: (__dirname + `/musicas/${musicid}.mp3`),
                            name: `${musicid}.mp3`
                        }],
                    });
                } catch (e) {
                    return message.channel.send(`${message.author}, Error ao tentar converter a música!`);
                }

Answer 1

我猜你想发送附加文件的URL。不幸的是，您只能在首先发送附件本身之后发送URL。

const image = await message.channel.send({ files: [{ attachment: `full-path`, name: `something.mp3` }] });
return message.channel.send({ content: `${image.attachments.first().proxyURL}` });

在discord.js文档这里中阅读更多关于它的信息。