language_tool如何导入类

Question

我对颤振没有多少经验。

我想使用language_tool库进行Dart和颤振。(https://pub.dev/packages/language_tool)

我创建了下面的脚本，并希望在屏幕上显示一个具有所有.issueTypes的.issueTypes。

但是我不知道如何从WritingMistake包导入language_tool类。

你知道我怎么解决吗？

void main() => runApp(mainApp());

class mainApp extends StatelessWidget {
  @override
  Widget build(BuildContext context) {
    return MaterialApp(
      home: Chat(),
    );
  }
}

class Chat extends StatefulWidget {
  const Chat({Key? key}) : super(key: key);

  @override
  _ChatState createState() => _ChatState();
}

class _ChatState extends State<Chat> {
  String text = 'Helllo I am Gabriele';

  Future<List<WritingMistake>> tool(String text) async {
    var tool = LanguageTool();
    var result = tool.check(text);
    var correction = await result;

    print(correction);

    List<WritingMistake> mistakes = [];

    for (var m in correction) {

      WritingMistake mistake = WritingMistake(m['offset'], m['length'],
          m['issueType'], m['issueDescription'], m['replacements']);

      mistakes.add(mistake);
    }

    print(mistakes.length);

    return mistakes;
  }

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      body: SafeArea(
        child: FutureBuilder(
          future: tool(text),
          builder: (BuildContext context, AsyncSnapshot snapshot) {
            if (snapshot.data == null) {
              return Container(
                child: Center(
                  child: Text('Loading...'),
                ),
              );
            } else {
              return ListView.builder(
                itemCount: snapshot.data.length,
                itemBuilder: (BuildContext context, int index) {
                  return ListTile(
                    title: Text(snapshot.data[index].issueType),
                  );
                },
              );
            }
          },
        ),
      ),
    );
  }
}

希望有人能帮我。谢谢。

Answer 1

我下载了包，复制了您的代码，只有一个错误，在行中：

WritingMistake mistake = WritingMistake(m['offset'], m['length'],
          m['issueType'], m['issueDescription'], m['replacements']);

我用这个代码解决了这个问题：

  WritingMistake mistake = WritingMistake(message: m.message, offset: m.offset, length: m.length,
      issueType: m.issueType, issueDescription: m.issueDescription, replacements: m.replacements);

程序输出：

​

​

如果我将短语："Helllo I am Gabriele"改为"Hello I am Gabriele"，则输出将为“未分类”。

希望这能帮上忙！