如何将表参数从NLUA函数传递给C#方法？

Question

我在一个C#项目中使用NLUA。我使用以下代码注册一个C#方法，以便在LUA (NLUA)环境中可用(和工作)：

// C# code to register the methoin LUA environment:
Lua state = new Lua();
state["MyLog"] = new LuaLog();

// C# Class and Method:
public class LuaLog {
  public void write(string aLog) {
      LogManager.addLog(aLog);
  }
}

--LUA CODE TO CALL C# METHOD:
MyLog:write("This is a log string")

好吧，我想调用"MyLog:write()“，但是传递一个表，而不是一个字符串。例如：

MyLog:write( {LogText="This is a log string", LogType="INFO"} )

有可能吗？如何编写C#方法将该参数作为表读取？我试过：

// C# CODE:
public void write(Dictionary<string, string> aLog)

public void write(List<string> aLog)

但什么都不管用。你能帮帮我吗？

谢谢!

Answer 1

实际例子：

public class Example {
    public Dictionary<string, string> MethodCalledFromLua(Object aInput) {
    
      //
      // READ LUA ARGUMENTS WITH THE PROPER TYPE
      //
      if(aInput is LuaTable) {
        LuaTable theLuaTable = aLuaTable as LuaTable;
        Console.WriteLine("LUA TABLE: " + theLuaTable["name"] + " --> " + theLuaTable["surname"]);
      }
    
      if(aInput is string) {
        string theString = aInput as string;
        Console.WriteLine("STRING: " + theString);
      }
    
      //
      // RETURN A DICTIONARY TO LUA (NLUA)
      // (remember that LUA is case-sensitive!)
      //
      Dictionary<string, string> ret = new Dictionary<string, string>();
    
      Dictionary<string, object> editor = FormsManager.newEditor(); 
      ret["DATA_1"] = "My Name";
      ret["DATA_2"] = "My Last Name";
    
      return ret;
        }
      }

从C#注册NLUA类：

luaState["MyExample"] = new Example();

LUA代码：

local ret = MyExample:MethodCalledFromLua( {name = "the name", surname = "the surname" } )
print(ret.DATA_1)