将过滤添加到动态创建的模式中，使用hotchocolate (GraphQL)

Question

我正在使用hotchocolate (v12)的最新版本中引入的新接口(V12)来动态创建所有类型的模式。(https://chillicream.com/blog/2021/09/27/hot-chocolate-12#dynamic-schemas)

效果很好。但是现在我很难找到如何使用这个策略在我的类型上添加过滤(因为我不能使用anotations，而且描述符也不像它在文档上的操作(https://chillicream.com/docs/hotchocolate/fetching-data/filtering) )。

到目前为止我尝试过的是：

我的依赖注入：

// code omitted 
builder.Services
       .AddGraphQLServer()
       .AddTypeModule<DynamicTenantSchemaTypeModule>()
       .AddFiltering();

关于ITypeModule实现(DynamicTenantSchemaTypeModule)：

    //code omitted
    public async ValueTask<IReadOnlyCollection<ITypeSystemMember>> CreateTypesAsync(IDescriptorContext context, CancellationToken cancellationToken)
    {
            var types = new List<ITypeSystemMember>();
            var queryType = new ObjectTypeDefinition("Query");
            var schemas = await _documentSchemaRepository.GetSchemasAsync();
            foreach (var schema in schemas)
            {
                var schemaNamePascalCase = schema.Name!.ToPascalCase();
                var schemaNamePluralCamelCase = schema.PluralName!.ToCamelCase();
                var objectTypeDefinition = new ObjectTypeDefinition(schemaNamePascalCase);
                await AddFieldsAsync(types, schema, objectTypeDefinition, schema.Properties);
                queryType.Fields.Add(new ObjectFieldDefinition(schemaNamePluralCamelCase)
                {
                    Type = TypeReference.Parse($"[{schemaNamePascalCase}]"),
                    Resolver = async (ctx) =>
                    {
                        var documents = await _documentRepository.GetDocumentsAsync(schema.Id);
                        return documents;
                    }
                }
                .ToDescriptor(context)
                .UseFiltering()
                .ToDefinition());
                types.Add(ObjectType.CreateUnsafe(objectTypeDefinition));
            }
            types.Add(ObjectType.CreateUnsafe(queryType));
            return types;
}
//code omitted

但是它抛出以下异常：

HotChocolate.SchemaException: For more details look at the `Errors` property.

1. No default filter convention found. Call `AddFiltering()` on the schema builder.

   at HotChocolate.Data.FilterDescriptorContextExtensions.<>c__DisplayClass1_0.<GetFilterConvention>b__0()
   at HotChocolate.Types.Descriptors.DescriptorContext.GetConventionOrDefault[T](Func`1 defaultConvention, String scope)
   at HotChocolate.Data.FilterDescriptorContextExtensions.GetFilterConvention(IDescriptorContext context, String scope)
   at HotChocolate.Types.FilterObjectFieldDescriptorExtensions.<>c__DisplayClass5_0.<UseFiltering>b__1(IDescriptorContext c, ObjectFieldDefinition definition)
   at HotChocolate.Types.Descriptors.DescriptorBase`1.<>c__DisplayClass19_0.<OnBeforeCreate>b__0(IDescriptorContext c, IDefinition d)
   at HotChocolate.Types.Descriptors.DescriptorBase`1.CreateDefinition()
   at HotChocolate.Types.Descriptors.DescriptorExtensions.ToDefinition[T](IDescriptor`1 descriptor)

对如何正确添加过滤中间件有什么想法吗？谢谢!

Answer 1

到目前为止，我得到了一些领域的过滤工作，我不知道它从哪里来

1. 在配置

的代码中应用筛选器约定

descriptor.UseFiltering<MyFilterConvention>(f =>
{
  f.Name(schemaNamePascalCase + "OperationFilterInput");
});

从class

• configure派生自定义过滤器约定(

1. )以添加提供程序：

，从而创建自定义筛选器约定MyFilterConvention

protected override void Configure(IFilterConventionDescriptor descriptor)
{
  descriptor.AddDefaults();
  descriptor.Provider(new QueryableFilterProvider(x => 
    x.AddDefaultFieldHandlers()));
}

这是对象Foo的结果。

foos (
    where: FooOperationFilterInput
): [Foo]

input FooOperationFilterInput {
  and: [FooOperationFilterInput!]
  or: [FooOperationFilterInput!]
  scope: StringOperationFilterInput
}

input StringOperationFilterInput {
  and: [StringOperationFilterInput!]
  or: [StringOperationFilterInput!]
  eq: String
  neq: String
  ... the rest is omitted for brevity ...
}