这是我所拥有的数据的dput。我只包括了数据的头,因为这是一个相当大的数据集,但我认为,考虑到我的问题,这应该足够了:
structure(list(Prioritising.workload = c(2L, 2L, 2L, 4L, 1L,
2L), Writing.notes = c(5L, 4L, 5L, 4L, 2L, 3L), Workaholism = c(4L,
5L, 3L, 5L, 3L, 3L), Reliability = c(4L, 4L, 4L, 3L, 5L, 3L),
Self.criticism = c(1L, 4L, 4L, 5L, 5L, 4L), Loneliness = c(3L,
2L, 5L, 5L, 3L, 2L), Changing.the.past = c(1L, 4L, 5L, 5L,
4L, 3L), Number.of.friends = c(3L, 3L, 3L, 1L, 3L, 3L), Mood.swings = c(3L,
4L, 4L, 5L, 2L, 3L), Socializing = c(3L, 4L, 5L, 1L, 3L,
4L), Energy.levels = c(5L, 3L, 4L, 2L, 5L, 4L), Interests.or.hobbies = c(3L,
3L, 5L, NA, 3L, 5L)), row.names = c(NA, 6L), class = "data.frame")我试图找出所有这些变量的离群值。如果我单独这样做,我将得到与尼罗河一样长的以下代码:
#### EFA Personality Data Check ####
ef.personality %>%
identify_outliers(Prioritising.workload) %>%
select(is.extreme)
ef.personality %>%
identify_outliers(Writing.notes) %>%
select(is.extreme)
ef.personality %>%
identify_outliers(Workaholism) %>%
select(is.extreme)
ef.personality %>%
identify_outliers(Reliability) %>%
select(is.extreme)
ef.personality %>%
identify_outliers(Self.criticism) %>%
select(is.extreme)
ef.personality %>%
identify_outliers(Loneliness) %>%
select(is.extreme)
ef.personality %>%
identify_outliers(Changing.the.past) %>%
select(is.extreme)
ef.personality %>%
identify_outliers(Number.of.friends) %>%
select(is.extreme)
ef.personality %>%
identify_outliers(Mood.swings) %>%
select(is.extreme)
ef.personality %>%
identify_outliers(Socializing) %>%
select(is.extreme)
ef.personality %>%
identify_outliers(Energy.levels) %>%
select(is.extreme)
ef.personality %>%
identify_outliers(Interests.or.hobbies) %>%
select(is.extreme)有什么命令可以让这件事变得更简单吗?我在考虑某种循环,它可以检查每个变量并为每个变量返回异常值,但我不知道如何实现这一点。我也对不依赖rstatix的解决方案持开放态度。
发布于 2022-03-24 04:33:42
rstatix的美妙之处在于它是管道友好的。因此,您可以在tidyverse框架中使用它。tidyverse需要长格式的数据.您可以使用以下代码
library(tidyverse)
library(rstatix)
ef.personality %>%
mutate(id = seq(1, nrow(ef.personality),1)) %>% #To create a unique column required to make that data in long form
pivot_longer(-id) %>% #To make the data in long form required for `tidyverse`
group_by(name) %>% #Based on which column you want aggregate
identify_outliers(value) %>%
select(name, is.extreme)https://stackoverflow.com/questions/71597008
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