如何使它在同一行上打印输出？

Question

我正试图打开两个文件，收集2010至2019年的信息，并报告当年索赔的平均值和标准差。

mean_file = open('data/mean.txt', 'r')
std_file = open('data/std.txt', 'r')
count = 2009

for line in std_file:
    std = float(line)
    for line in mean_file:
        mean = float(line)
    count += 1
    print('Year',count, 'Mean:', mean, 'Standard Deviation:', std)

mean_file.close()
std_file.close()

上面有密码。我得到的输出是

Year 2019 Mean: 217557.4 Standard Deviation: 82296.33
Year 2019 Mean: 217557.4 Standard Deviation: 77808.0
Year 2019 Mean: 217557.4 Standard Deviation: 66939.77
Year 2019 Mean: 217557.4 Standard Deviation: 65486.56
Year 2019 Mean: 217557.4 Standard Deviation: 59126.12
Year 2019 Mean: 217557.4 Standard Deviation: 58712.14
Year 2019 Mean: 217557.4 Standard Deviation: 55465.54
Year 2019 Mean: 217557.4 Standard Deviation: 44621.54
Year 2019 Mean: 217557.4 Standard Deviation: 47821.1
Year 2019 Mean: 217557.4 Standard Deviation: 43170.7

每次我改变缩进的位置，它就会给出不同的答案。我希望平均偏差和标准差同时打印在同一行上，就像下面的输出一样。我希望输出如下所示。如何使它与下面的输出完全相同？

Year 2010 Mean: 455692.98 Standard Deviation: 82296.33
Year 2011 Mean: 409110.4 Standard Deviation: 77808.0
Year 2012 Mean: 372226.67 Standard Deviation: 66939.77
Year 2013 Mean: 341826.79 Standard Deviation: 65486.56
Year 2014 Mean: 306567.67 Standard Deviation: 59126.12
Year 2015 Mean: 276956.5 Standard Deviation: 58712.14
Year 2016 Mean: 263900.21 Standard Deviation: 55465.54
Year 2017 Mean: 243116.25 Standard Deviation: 44621.54
Year 2018 Mean: 220894.98 Standard Deviation: 47821.1
Year 2019 Mean: 217557.4 Standard Deviation: 43170.7

Answer 1

for sline, mline in zip(std_file, mean_file):
   std = float(line)
   mean = float(line)
   count = count+1
   print('Year',count, 'Mean:', mean, 'Std:', std)