SELECT *
FROM Under_200 u
WHERE u.Chance_of_Gain_under > 75;
SELECT *
FROM Over_200 o
WHERE o.Chance_of_Gain_over > 75;我试图以横向的方式连接两个单独的MySQL查询。例如Pandas连接在轴= 1的地方。
发布于 2022-03-16 23:22:14
如果符号是列分母,则可以使用位查询作为子查询。
SELECT u.*,o.*
FROM
(SELECT *
FROM Under_200
WHERE Chance_of_Gain_under > 75) u
JOIN
(
SELECT *
FROM Over_200
WHERE Chance_of_Gain_over > 75) o ON o.Symbol = u.Symbol发布于 2022-03-16 23:25:53
WITH custom_tab1
AS (SELECT *
FROM under_200
WHERE chance_of_gain_under > 75),
custom_tab2
AS (SELECT *
FROM over_200
WHERE chance_of_gain_over > 75)
SELECT *
FROM custom_tab1 ct1
INNER JOIN custom_tab2 ct2
ON ct1.symbol = ct2.symbol; 看看这个有用不管用。我使用一个常见的表表达式进行了求解。
https://stackoverflow.com/questions/71505177
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