将CommonJS转换为ES模块

Question

我将编码作为业余爱好，目前正在从事一个新的NodeJS项目。以我有限的知识，我有一种感觉，与ES模块的工作是未来(如果我错了，纠正我)。因此，我想重写一些我有到ES模块中的CommonJS脚本。

我被困在试图转换它的下面一行：require('./app/routes/routes')(app) (我不明白“(应用程序)”部分到底做了什么)。

routes.js:

module.exports = app => {
    const recipe = require('../controllers/recipe-controller.js');
    var router = require('express').Router();
    // Create a new Recipe
    router.post('/recipe', recipe.create);
    app.use('/api/recipes', router);
  };

server.js:

import express from 'express'
import db from './app/models/index'

const app = express();

app.get('/', (req, res) => {
  res.json({ message: 'Welcome to bezkoder application.' });
});
require('./app/routes/routes')(app);
const PORT = process.env.PORT || 8080;
app.listen(PORT, () => {
  console.log(`Server is running on port ${PORT}.`);
});

Answer 1

这一行：

require('./app/routes/routes')(app)

是导入一个函数，然后调用它。这在逻辑上与以下几点相同：

const init = require('./app/routes/routes');
init(app);

因此，要将其转换为ESM，您需要更改路由模块以导出一个命名函数。然后您可以导入这个命名的函数，然后调用它(将app传递给它)。

routes.js

import express from 'express';
import recipe from '../controllers/recipe-controller.js';

export function init(app) {
    // Create a new Recipe
    const router = express.Router();
    router.post('/recipe', recipe.create);
    app.use('/api/recipes', router);
}

server.js

import express from 'express'
import db from './app/models/index'
import init from './app/routes/routes';

const app = express();

app.get('/', (req, res) => {
  res.json({ message: 'Welcome to bezkoder application.' });
});

init(app);

const PORT = process.env.PORT || 8080;
app.listen(PORT, () => {
  console.log(`Server is running on port ${PORT}.`);
});