如何通过函数返回下载的文件？

Question

在发帖之前，我只想提出两件事：

appreciated.

• It's

1. I从不到一个月就开始编程，所以任何增强、替代、精进或过度的解释，都是Boldy关于堆栈溢出的第一篇文章，希望我能正确地构造它。

因此，我试图定义一个函数" download ( url )“，该函数应该从我刚刚创建的函数中调用的url中下载一个带有进度条的文件。

我让它看起来像这样：

def download(url):
    import requests
    from progress.bar import Bar
    
    file = requests.get(url, stream=True)
    dictdata = eval(str(file.headers))
    total_length = dictdata["Content-Length"]
    with Bar("Downloading...") as bar:
        for chunk in file.iter_content(chunk_size=(int((int(total_length))/100))):
                <Here goes something that writes it down to a variable or something like 
                that but I don't know how that's called yet.> 
                bar.next()
    return <the variable or whatever it'll be.>

顺便说一句，我希望它能这样工作：

file = download(example)

那我该怎么做？

Answer 1

也许你想要存储字节的chunk？

data = bytearray()
with Bar("Downloading...") as bar:
    for chunk in file.iter_content(chunk_size=(int((int(total_length))/100))):
        data += chunk
        bar.next()
return data