如何访问字典中列表中的全部值，而不是单个字符？

Question

我对编码非常陌生，我已经试着查找并重新阅读我的笔记，但我想不出这一条。我试图检索字典(all_customers)中列表中的单个值。当我试图检索一个数字时的例子：

print(f"Earnings from how many months they subscribed for = ${(all_customers['customer1'][0])}")

但是，在索引时，它检索单个字符(如上面的示例所示，它返回括号：[)，而不是完整的数字(如151)。这应该更像:如果我为第一个客户输入25 for months_subscribed、10 for ad_free_months和5 for videos_on_demand_purchases，那么all_customers['customer1']应该返回[151, 20, 139.95]，而上面我试图打印的示例应该是“他们订阅=$151的月的收益”，而不是“他们订阅= [”订阅了多少个月的收益。

def subscription_summary(months_subscribed, ad_free_months, video_on_demand_purchases):  

    #price based on months subscribed
    if int(months_subscribed) % 3 == 0:
        months_subscribed_price = int(months_subscribed)/3*18
    elif int(months_subscribed) > 3:
        months_subscribed_price = int(months_subscribed)%3*7 + int(months_subscribed)//3*18
    else:
        months_subscribed_price = int(months_subscribed)*7
        
    #price of ad free months
    ad_free_price = int(ad_free_months)*2

    #price of on demand purchases
    video_on_demand_purchases_price = int(video_on_demand_purchases)*27.99

    customer_earnings = [months_subscribed_price, ad_free_price, video_on_demand_purchases_price]

    return customer_earnings
#Loop through subscription summary 3 times, to return 3 lists of customers earnings and add them to a dictionary
all_customers={}

for i in range(3):
    months_subscribed = input("How many months would you like to purchase?: ")
    ad_free_months = input("How many ad-free months would you like to purchase?: ")
    video_on_demand_purchases = input("How many videos on Demand would you like to purchase?: ")

    #congregate individual customer info into list and run it through the function
    customer = [months_subscribed, ad_free_months, video_on_demand_purchases]

    indi_sub_sum = subscription_summary(customer[0], customer[1], customer[2])
    #congregate individual customers subscription summary lists into a dictionary
  
    all_customers[f"customer{i+1}"] = f"{indi_sub_sum}"

我希望这是一个可以问的问题！对不起，我对这件事很陌生：)

Answer 1

尝试打印出all_customers字典，您将看到问题所在：

>>> all_customers
{'customer1': '[32, 8, 83.97]', 'customer2': '[25, 6, 55.98]', 'customer3': '[18.0, 4, 27.99]'}

你所有的列表实际上都是字符串。因为这句话：

all_customers[f"customer{i+1}"] = f"{indi_sub_sum}"

您要给它分配一个字符串，而不是列表。改为：

all_customers[f"customer{i+1}"] = indi_sub_sum

应该为你解决这个问题。