如何在具有多个条件的python中循环

Question

我目前正在学习Python基础知识，并陷入了这个While循环中：

numbers = [1, 3, 6, 9]
n = int(input('Type a number between 0 and 9: '))
while 0 > n > 9:
    n = int(input('Type a number between 0 and 9: '))
if n in numbers:
    print('This number is on the number list!')

在这里输入图像描述

我想要的是一个循环，直到用户引入一个介于0到9之间的数字，然后检查它是否在列表中。我已经在网上搜索过了，但是我找不到我错的地方。

Answer 1

您的循环应该在n < 0或n > 9时继续。

while n < 0 or n > 9:
    ...

根据德摩根定律，否定这一条件很可能是你的目的：

while not (0 <= n <= 9):
    ...

Answer 2

你可以这样做：

def loop_with_condition():
    numbers = [1, 3, 6, 9]
    while True:
        n = int(input('Type a number between 0 and 9: '))
        if n < 0 or n > 10:
            print('Out of scope!')
            break
        if n in numbers:
            print('This number is on the number list!')


if __name__ == '__main__':
    loop_with_condition()

Answer 3

给你:)

numbers = [1, 3, 6, 9]

class loop_with_condition:
    def __init__(self):
        self.num = int(input('Choose a number from 0 to 9: '))
        self.check()
    
    def check(self):
        if self.num not in numbers:
            print(f'Number {self.num} not in numbers')
            self.__init__()
            return
        else:
            print(f'Number {self.num} is in numbers')

现在要做的就是调用类loop_with_condition()