PHP加密(密钥大小为128 / 8)等效于CryptoJS

Question

我是PHP的新手，我试图在PHP中实现等效的CryptoJS AES加密。我看到了这个post，但不幸的是，我无法实现同样的目标。我在PHP代码中以加密字符串的形式得到了不同的输出。

我哪里出错了？

Javascript代码

const customerObject = {
  CustomerName: "test",
  EmailID: "tester@test.com",
  Street: "Test",
  City: "London",
  Country: "United Kingdom",
  ZipCode: "XXX XXX",
};

const token = "8056483646328123";

const key = CryptoJS.enc.Utf8.parse(token);
const iv = CryptoJS.enc.Utf8.parse(token);

const returnEncrypted = CryptoJS.AES.encrypt(
  CryptoJS.enc.Utf8.parse(customerObject),
  key,
  {
    iv: iv,
    keySize: 128 / 8,
    mode: CryptoJS.mode.CBC,
    padding: CryptoJS.pad.Pkcs7,
  }
);

PHP代码

 <?php
    
    $customer = [
       'CustomerName' => "test",
       'EmailID' => "tester@test.com",
       'Street' => "Test",
       'City' => "London",
       'Country' => "United Kingdom",
       'ZipCode' => "XXX XXX",
    ];
    
    
    $plaintext  = json_encode($customer);
    $method     = 'AES-128-CBC';
    
    $key = hex2bin("8056483646328123");
    $iv  = hex2bin("8056483646328123");
    
    $ciphertext = openssl_encrypt(
       $plaintext,
       $method,
       $key,
       OPENSSL_RAW_DATA,
       $iv
    );
    
    
    $ciphertext = base64_encode($ciphertext);

    echo $ciphertext;
    
    ?>

Answer 1

正如@Topaco在注释中指出的，不能对键和IV进行十六进制解码，即删除hex2bin()。

修正后的代码如下所示。

<?php
    
    $customer = [
       'CustomerName' => "test",
       'EmailID' => "tester@test.com",
       'Street' => "Test",
       'City' => "London",
       'Country' => "United Kingdom",
       'ZipCode' => "XXX XXX",
    ];
    
    
    $plaintext  = json_encode($customer);
    $method     = 'AES-128-CBC';
    
    $key = "8056483646328123";
    $iv  = "8056483646328123";
    
    $ciphertext = openssl_encrypt(
       $plaintext,
       $method,
       $key,
       OPENSSL_RAW_DATA,
       $iv
    );
    
    
    $ciphertext = base64_encode($ciphertext);

    echo $ciphertext;
    
    ?>