SwiftUI如何使用FBSDKShareKit和ShareDialog共享Facebook的URL？

Question

我试着在这和这这样的帖子中寻找解决方案，人们问了同样的问题:如何使用SwiftUI共享Facebook的url

我甚至尝试过这个职位，有人问我如何使用SwiftUI导出文件，但我的问题是，特别是Facebook，因为我没有问题将urls共享到诸如Whatsapp之类的应用程序。但是我没有找到答案..。

UIKit

通过阅读Facebook的开发人员文档，我找到了一种使用UIKit共享帖子的方法。

我创建了一个非常简单的示例项目，以确保我理解这个主题。下面是UIKit中的示例项目：

import UIKit
import FBSDKShareKit

class ProfileViewController: UIViewController {
    
    
    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view.
    }


    @IBAction func share(_ sender: UIButton) {
        shareLink(url: URL(string: "http://www.apple.com")!)
    }
    
    func shareLink(url: URL) {
        let content = ShareLinkContent()
        content.contentURL = url

        let dialog = ShareDialog(
            fromViewController: self,
            content: content,
            delegate: nil
        )
        dialog.show()
    }
}

幸运的是，这很快就成功了。通过使这个项目发挥作用，我确认我没有忘记将我的AppBundleID链接到Facebook，或者忘记在我的info.plist中添加我的FacebookAppID或任何其他需要的文件。

SwiftUI

然后，我尝试在SwiftUI中复制相同的项目，看看是否能让它正常工作。我使用ViewControllerRepresentable能够将UIActivityViewController包含到SwiftUI中。

使用UIActivityViewController的原因是我希望用户选择他们想要共享的网址(Whatsapp、Twitter、Facebook等)。

以下是代码：

ContentView

struct ContentView: View {
    @State var showSharingView = false
    var body: some View {
        Button("Share Link") {
            showSharingView.toggle()
        }
        
        .sheet(isPresented: $showSharingView) {
           ActivityViewController(activityItems: [URL(string: "https://www.apple.com/")!])
        }
    }
}

UIViewControllerRepresentable

struct ActivityViewController: UIViewControllerRepresentable {

    var activityItems: [URL]
    var applicationActivities: [UIActivity]? = nil
    
    func makeUIViewController(context: UIViewControllerRepresentableContext<ActivityViewController>) -> UIActivityViewController {
        
        let controller = UIActivityViewController(activityItems: activityItems, applicationActivities: applicationActivities)
        
        controller.completionWithItemsHandler = { (activityType, completed, returnedItems, error) in
            
            if activityType == .postToFacebook {     
                shareLink(from: activityItems.first!)
            }
            
        }
        return controller
    }

    func updateUIViewController(_ uiViewController: UIActivityViewController, context: UIViewControllerRepresentableContext<ActivityViewController>) {}

    func shareLink(from url: URL) {
        
        // controller was created so I would have a UIViewControllerType to put as a parameter for fromViewController in ShareDialog, even though I don't think it fits
        let controller = UIActivityViewController(activityItems: activityItems, applicationActivities: applicationActivities)
        
        
        let content = ShareLinkContent()
        content.contentURL = url
        
        let dialog = ShareDialog(fromViewController: controller, content: content, delegate: nil)
        dialog.show()
    }
    
}

这段代码无法工作，因为我假设初始化controller时使用的是ShareDialog变量。(self也不起作用，因为"XCode无法将'ActivityViewController‘类型的值转换为预期的参数类型’UIViewController？‘’“)

问题

Facebook开发人员文档告诉我，为了共享一个链接，我需要编写以下代码：

guard let url = URL(string: "https://developers.facebook.com") else {
    // handle and return
}

let content = ShareLinkContent()
content.contentURL = url

let dialog = ShareDialog(
    viewController: self, //<--this has been changed to 'fromViewController'
    content: content,
    delegate: self
)
dialog.show()

然而，SwiftUI不适用于ViewControllers。如何创建一个ViewController作为fromViewController中ShareDialog中的一个参数，以便成功地将我的URL共享到Facebook？

Answer 1

像这样使用，

guard let url = URL(string: "https://developers.facebook.com") else {
    // handle and return
}

let content = ShareLinkContent()
content.contentURL = url

let dialog = ShareDialog(
    viewController: UIApplication.shared.windows.first!.rootViewController,
    content: content,
    delegate: UIApplication.shared.windows.first!.rootViewController
)
dialog.show()