小组后得到的值是在gremlin吗？

Question

g.V('JobDefinition1').out("JobDefinitionToJobHistory").has("Timestamp", between("2022-02-01T00:00:00Z", "2022-02-03T00:00:00Z")).group().by("ttl").by(limit(1))

上面有一个gremlin查询，结果如下。

[
  {
    "776": [
      {
        "id": "JobHistory-2-1-2022 12:19:15 AM",
        "label": "JobHistory",
        "type": "vertex",
        "properties": {
          "Timestamp": [
            {
              "id": "6d187ccf-160d-4d87-a360-48526b7a1461",
              "value": "2022-02-01T00:00:00Z"
            }
          ],
          "ttl": [
            {
              "id": "JobHistory-2-1-2022 12:19:15 AM|ttl",
              "value": "776"
            }
          ]
        }
      }
    ],
    "888": [
      {
        "id": "JobHistory-2-1-2022 12:19:15 AM",
        "label": "JobHistory",
        "type": "vertex",
        "properties": {
          "Timestamp": [
            {
              "id": "6d187ccf-160d-4d87-a360-48526b7a1461",
              "value": "2022-02-01T00:00:00Z"
            }
          ],
          "ttl": [
            {
              "id": "JobHistory-2-1-2022 12:19:15 AM|ttl",
              "value": "888"
            }
          ]
        }
      }
    ]
  }
]

但是我只想得到一个接一个的结果的值，例外结果如下所示。我想要不带键的groupby结果值(正如您所看到的，例外结果没有键信息，如"776“和"888")。有什么方法能帮我实现这个目标吗？希望你能帮我个忙。谢谢!

[
  {
    "id": "JobHistory-2-1-2022 12:19:15 AM",
    "label": "JobHistory",
    "type": "vertex",
    "properties": {
      "Timestamp": [
        {
          "id": "6d187ccf-160d-4d87-a360-48526b7a1461",
          "value": "2022-02-01T00:00:00Z"
        }
      ],
      "ttl": [
        {
          "id": "JobHistory-2-1-2022 12:19:15 AM|ttl",
          "value": "776"
        }
      ]
    }
  }
  ,
  {
    "id": "JobHistory-2-1-2022 12:19:15 AM",
    "label": "JobHistory",
    "type": "vertex",
    "properties": {
      "Timestamp": [
        {
          "id": "6d187ccf-160d-4d87-a360-48526b7a1461",
          "value": "2022-02-01T00:00:00Z"
        }
      ],
      "ttl": [
        {
          "id": "JobHistory-2-1-2022 12:19:15 AM|ttl",
          "value": "888"
        }
      ]
    }
   }
]

Answer 1

可以从带有Map的select(values)中获取值。

gremlin> g.V().groupCount().by(label)
==>[software:2,person:4]
gremlin> g.V().groupCount().by(label).select(values)
==>[2,4]