专家们,日安!
我想复制一个文件并根据输入值通过单击按钮重命名它。我的代码不起作用。没有复制或重命名的文件。这是我的密码:
<?php
error_reporting(0);
if($_POST['action'] == 'call_this') {
echo Success!;
};
$file = 'data.php';
$newfile = '$_GET['subject'].php';
echo copy($file, $newfile);
?>
<form action="<?php echo $newfile ?>" method="get">
<input type="text" name="subject" required>
<button type="submit"><a href="" onclick="change()">Change</a></button>
</form>
<script>
function change() {
$.ajax({
type: "POST",
url: 'data.php',
data:{action:'call_this'},
success:function(html) {
alert(html);
}
});
}
</script>发布于 2022-02-14 14:35:43
我想这就是你要找的:
<html>
<body>
<form method="post" action="copy.php">
<input type="text" placeholder="new name" name="newFileName"/>
<input type="submit" value="Change"/>
</form>
</body>
</html>copy.php:
<?php
$file = 'sample.txt';
$newfile = $_POST["newFileName"].'.txt';
if (!copy($file, $newfile)) {
echo "failed to copy";
}else {
echo "copy with new name";
}
?>https://stackoverflow.com/questions/71112963
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