新增python在打印4个变量时遇到问题

Question

adding = int(5+3)
subtract = int(10-2)
multiplication = int(2*4)
division = int(16/2)
print (str(adding,"\n",subtract,"\n",multiplication,"\n",division))

im获取一个typeError: TypeError: str()最多接受3个参数(给定7个)

Answer 1

解决方案：只是从下面修改这段代码

print (str(adding,"\n",subtract,"\n",multiplication,"\n",division))

对这个。

print (adding,"\n",subtract,"\n",multiplication,"\n",division)

原因：str()是一个类型转换方法。你不需要把每一件事都打出来。

供参考：https://www.geeksforgeeks.org/type-casting-in-python-implicit-and-explicit-with-examples/

Answer 2

将str看作一个接受变量并将其转换为字符串的函数。将多个变量传递给str()，用逗号分隔，将不会将字符串函数应用于每个变量。相反，这意味着它们是函数的参数。如果要将每个变量转换为

adding = str(int(5+3))
subtract = str(int(10-2))
multiplication = str(int(2*4))
division = str(int(16/2))
print (adding,"\n",subtract,"\n",multiplication,"\n",division)

注意，print函数为打印目的接受多个参数。

Answer 3

要将integer转换为string，需要分别使用str()每个变量。此外，您还可以使用+作为concat运算符，以避免额外的空间。

print(str(adding)+"\n"+str(subtract)+"\n"+str(multiplication)+"\n"+str(division))