矩阵相减

Question

我试图创建一个循环来执行以下操作：

两个矩阵，A和B，我想分别从B的每个元素中减去A中的第一个元素，然后转到A的下一个元素，然后将结果保存到一个新的矩阵C中。

A和B= 2x2矩阵的示例：

a1 = np.subtract(b[0, 0], a[0, 0]) #difference between all elements in b and first element in a
a2 = np.subtract(b[0, 1], a[0, 0])

a3 = np.subtract(b[1, 0], a[0, 0])
a4 = np.subtract(b[1, 0], a[0, 0])

b1 = np.subtract(b[0, 0], a[0, 1]) #difference between all elements in b and second element in a
b2 = np.subtract(b[0, 1], a[0, 1])

b3 = np.subtract(b[1, 0], a[0, 1])
b4 = np.subtract(b[1, 1], a[0, 1])

c1 = np.subtract(b[0, 0], a[1, 0]) #difference between all elements in b and third element in a
c2 = np.subtract(b[0, 1], a[1, 0])

c3 = np.subtract(b[1, 0], a[1, 0])
c4 = np.subtract(b[1, 1], a[1, 0])

d1 = np.subtract(b[0, 0], a[1, 1]) #difference between all elements in b and fourth element in a
d2 = np.subtract(b[0, 1], a[1, 1])

d3 = np.subtract(b[1, 0], a[1, 1])
d4 = np.subtract(b[1, 1], a[1, 1])

q = np.array([[a1, a2, a3, a4], [b1, b2, b3, b4], [c1, c2, c3, c4], [d1, d2, d3, d4]])
q

Answer 1

这是一个for循环，用于执行以下操作：

for ele in np.nditer(a):
   a_sub = np.tile(np.array([ele]),(b.shape[0], b.shape[1]))
   b -= a_sub