Mysql DISTINCT仍然返回重复值。

Question

如何避免在friends上复制我仍然可以得到两个bob而不是一个bob

我的桌子设置：

CREATE TABLE users(
    id INT PRIMARY KEY AUTO_INCREMENT,
    name VARCHAR(255)
);

INSERT INTO users (id, name)
VALUES (1, "Gregor"),
    (2, "Liza"),
    (3, "Matt"),
    (4, "Tim"),
    (5, "Lance"),
    (6, "Bob");
    
CREATE TABLE committee(
    id INT PRIMARY KEY AUTO_INCREMENT,
    user_id INT,
    friend_id INT,
    member_id INT,
    FOREIGN KEY (`user_id`) REFERENCES `users` (`id`),
    FOREIGN KEY (`friend_id`) REFERENCES `users` (`id`),
    FOREIGN KEY (`member_id`) REFERENCES `users` (`id`)
);
INSERT INTO committee (user_id, friend_id, member_id)
VALUES (3, 5, 1),
(4, 5, 1),
(3, 6, 2),
(3, 6, 2),
(4, 6, 2);

我使用的查询：

SELECT DISTINCT u.name,
       GROUP_CONCAT(f.name) AS friends
FROM committee c
INNER JOIN users u ON (u.id = c.user_id)
INNER JOIN committee c2 ON c2.user_id = c.user_id
INNER JOIN users AS f ON (f.id = c2.friend_id)
WHERE (c.member_id = 1)
GROUP BY u.id;

目前的结果：

name    friends
Matt    Lance,Bob,Bob
Tim Lance,Bob

我所期望的：

name    friends
Matt    Lance,Bob
Tim Lance,Bob

Answer 1

您只需要在DISTINCT中使用GROUP_CONCAT()：

SELECT u.name,
       GROUP_CONCAT(DISTINCT f.name) AS friends
................................................

请注意，SELECT DISTINCT ...在查询中没有意义，因为您使用的是GROUP BY，它为每个用户返回不同的行。

见演示。

Answer 2

您有不同的u.name，而不是f.name

尝尝这个

SELECT u.name,
       GROUP_CONCAT(distinct f.name) AS friends
FROM committee c
INNER JOIN users u ON (u.id = c.user_id)
INNER JOIN committee c2 ON c2.user_id = c.user_id
INNER JOIN users AS f ON (f.id = c2.friend_id)
WHERE (c.member_id = 1)
GROUP BY u.name;