AWS管道:如何将CodeBuild输出分配给Lambda代码？

Question

我有下面的AWS CDK管道，它可以工作。它基本上从两个不同的GitHub存储库(一个用于应用程序代码，一个用于cdk代码)获取源代码，并构建应用程序代码和cdk代码：

import * as cdk from 'aws-cdk-lib';
import * as codepipeline_actions from 'aws-cdk-lib/aws-codepipeline-actions';
import * as codepipeline from 'aws-cdk-lib/aws-codepipeline'
import * as codebuild from 'aws-cdk-lib/aws-codebuild'


import { Construct } from 'constructs';
import { CodePipeline, CodePipelineSource, ShellStep, CodeBuildStep } from 'aws-cdk-lib/pipelines';

export class CdkPipelineStack extends cdk.Stack {
    constructor(scope: Construct, id: string, props?: cdk.StackProps) {
        super(scope, id, props);

        // parameters
        const ConnectionArn = 'arn:aws:codestar-connections:region:account:connection/xxx-yyyy'


        // Source
        const cdkCodeStarConnection = CodePipelineSource.connection('owner/cdk-repo', 'master', {
            connectionArn: ConnectionArn
        })

        const lambdaCodeStarConnection = CodePipelineSource.connection('owner/lambda-repo', 'master', {
            connectionArn: ConnectionArn
        })

        // Building Lambda
        const lambdaBuildStep = new CodeBuildStep('BuildLambda', {
            buildEnvironment: {
                buildImage: codebuild.LinuxBuildImage.AMAZON_LINUX_2_3
            },
            input: lambdaCodeStarConnection,
            commands: ['variouscommands'],
            partialBuildSpec: codebuild.BuildSpec.fromObject({
                phases: {
                    install: {
                        "runtime-versions": {
                            python: "3.9"
                        },
                        "commands": ["python --version"]
                    }
                }
            })
        })

        const pipeline = new CodePipeline(this, 'Pipeline', {
            pipelineName: 'Pipeline',
            synth: new ShellStep('Synth', {
                input: cdkCodeStarConnection,
                commands: ['npm ci', 'npm run build', 'npx cdk synth', 'npx cdk ls'],
                additionalInputs: { 'lambda': lambdaBuildStep.addOutputDirectory('lambda') }
            })
        });
    }
}

现在，我想要实现的是能够将构建的代码(即lambdaBuildStep的输出)分配给另一个堆栈中的Lambda函数，即在下面的代码片段中，我希望assign_output_CodeBuildStep是lambdaBuildStep构建函数的s3位置：

import * as cdk from 'aws-cdk-lib';
import * as lambda from 'aws-cdk-lib/aws-lambda';

import { Construct } from 'constructs';
import { Bucket } from 'aws-cdk-lib/aws-s3'

import {backendBuildStep} from 'cdk-pipeline-stack'; 
import {ArtifactMap} from 'aws-cdk-lib/pipelines';


export class LambdaMonolith extends cdk.Stack {
    constructor(scope: Construct, id: string) {
        super(scope, id);

        const s3Code = assign_output_CodeBuildStep

        const LambdaFunction = new lambda.Function(this, 'MyFunction', {
            code: lambdaCode,
            runtime: lambda.Runtime.PYTHON_3_8,
            handler: 'lambda.handler',
          });
    }
};

我似乎找不到一种方法将这些信息从管道堆栈传输到Lambda堆栈。

任何帮助都将不胜感激。

谢谢!

Answer 1

所以我找到了解决办法。也许不是解决办法。的确，这似乎很复杂.我相信还有更好的方法。

因此，解决方案在于，CodePipeline构造中的CodePipeline将additionalInputs的输出(即前一个CodeBuildStep的结果，即lambdaBuildStep)附加到一个特定的目录中，这个目录是动态生成的，但存储在一个名为CODEBUILD_SRC_DIR_BuildLambda_lambda_repo的环境变量中，因此您可以看到，它是CodeBuildStep名称和repo的组合(将破折号改为下划线)。

因此，我的解决方案是使用这个环境变量作为我的Lambda代码资产。

        const LambdaFunction = new lambda.Function(this, 'MyFunction', {
            code: lambda.Code.fromAsset(process.env.CODEBUILD_SRC_DIR_BuildLambda_lambda_repo || ""),
            runtime: lambda.Runtime.PYTHON_3_8,
            handler: 'lambda.handler',
          });