脚本不在python中循环

Question

我正在做一个小的逃生室项目，当你完成一个动作时，它应该在完成某些动作后循环，但我的代码不会这样做。有人能帮我修好吗？这是我的密码。链接：(https://replit.com/@HoloGrain/Escape-Room-or-Bigger-Project#main.py)

    inventory= [] 

HP=100
ImplacedAnemo= False
ImplacedGeo= False
ImplacedElectro= False
print("Type every word beggining with a capital letter")

def Help():
    print("Commands:")
    print("Pick Up (Item))")
    print("Throw (Item) At (Other item)")
    print("Press (Item)")
    print("Hit (Item)")
    print("Open (Place)")
    print("Use (Item), (Command can only be used in battles)")
    print("Use (Item) On (Item or Door(ex. Room 1 Door))")
    print("Inventory", "(Opens inventory)")
    print("Check HP", "(Checks HP)")

def start():
    print("Welcome to HoloGrain's Escape room")
    print("You are locked in Tenshukaku")

def Room1():
    print("Paimon: Where are we")
    print("You: I don't know")
    print("Paimon: We should get out")

def Room1Command():
    ChainsLocked = True
    print("Room 1 Tools: Glass cage (contains sword), Paimon (If you get hungry and     talks), Rock, Door (locked using a sword lock), Chains (Locked using sword lock)")
    print("You're chained to the floor")
    Room1Start = input("What do you want to do?: ")
    if Room1Start == "Pick Up Rock":
        for x in inventory:
            if x == "Rock":
                print("Action: Hey, don't even try")
                Room1Command()
            elif x == "Dull Blade":
                print("Hey, don't even try")
                Room1Command()
            else:
                inventory.append("Rock")
                print("You have picked up a rock")
                Room1Command()
    elif Room1Start == "Throw Rock At Glass Cage":
        for x in inventory:
            if x == "Rock":
                print("Action: You succesfully threw the rock it shatters the cage and you  get the dull blade (6 DMG) and can ")
                inventory.remove('Rock')
                inventory.append("Dull Blade")
            else:
                print("You don't have a Rock to throw")
    elif Room1Start == "Use Dull Blade On Chains":
        for x in inventory:
            if x == "Dull Blade":
                if ChainsLocked == True:
                    ChainLocked = False
                    inventory.append("Chains")
                    print("You have unlocked the chains (Can stop one attack from an enemy and restarts mega-skills cooldown (One-time use)) and taken them")
                else:
                    print("Action: You've done this already")
    elif Room1Start == "Check HP":
        print(HP)
        Room1Command()
    elif Room1Start == "Check Inventory":
        print(inventory)
        Room1Command()
    elif Room1Start == "Use Dull Blade On Door":
        for x in inventory:
            if x == "Dull Blade":
                if ChainLocked == False:
                    print("You've opened the door")
        else:
            print("That doesn't work")
    else:
        print("Action: Undefined action in current state")
        Room1Command()
Help()
start()
Room1()
Room1Command()

Answer 1

您的代码中没有任何循环。它只调用所有函数一次，就结束了。

如果希望Room1Command始终运行，只需在Room1Command函数的最后一行中添加Room1Command()即可。所以看起来是这样：

def Room1Command():
    ChainsLocked = True
    print("Room 1 Tools: Glass cage (contains sword), Paimon (If you get hungry and     talks), Rock, Door (locked using a sword lock), Chains (Locked using sword lock)")
    print("You're chained to the floor")
    Room1Start = input("What do you want to do?: ")
    if Room1Start == "Pick Up Rock":
        for x in inventory:
            if x == "Rock":
                print("Action: Hey, don't even try")
                Room1Command()
            elif x == "Dull Blade":
                print("Hey, don't even try")
                Room1Command()
            else:
                inventory.append("Rock")
                print("You have picked up a rock")
                Room1Command()
    elif Room1Start == "Throw Rock At Glass Cage":
        for x in inventory:
            if x == "Rock":
                print("Action: You succesfully threw the rock it shatters the cage and you  get the dull blade (6 DMG) and can ")
                inventory.remove('Rock')
                inventory.append("Dull Blade")
            else:
                print("You don't have a Rock to throw")
    elif Room1Start == "Use Dull Blade On Chains":
        for x in inventory:
            if x == "Dull Blade":
                if ChainsLocked == True:
                    ChainLocked = False
                    inventory.append("Chains")
                    print("You have unlocked the chains (Can stop one attack from an enemy and restarts mega-skills cooldown (One-time use)) and taken them")
                else:
                    print("Action: You've done this already")
    elif Room1Start == "Check HP":
        print(HP)
        Room1Command()
    elif Room1Start == "Check Inventory":
        print(inventory)
        Room1Command()
    elif Room1Start == "Use Dull Blade On Door":
        for x in inventory:
            if x == "Dull Blade":
                if ChainLocked == False:
                    print("You've opened the door")
        else:
            print("That doesn't work")
    else:
        print("Action: Undefined action in current state")
        Room1Command()
    Room1Command()

通过这样做，每次用户输入命令并对其进行处理时，您的代码都将等待下一个输入。这意味着您的Room1Command函数将有一个循环。如果我对你的问题有了正确的理解，我认为这是可行的。

还请记住，名为Inventory的列表是空的，因此不能对其进行迭代。你应该先在里面放一些值。

Answer 2

雾

elif Room1Start == "Throw Rock At Glass 

在结尾没有一个"Room1Commande()“

Answer 3

所以我看到的第一件事是，你在一个空的列表中循环--所以这是不可能的。

也许你的意思是这样的：

def Room1Command():
    ChainsLocked = True
    print(
        "Room 1 Tools: Glass cage (contains sword), Paimon (If you get hungry and   talks), Rock, Door (locked using a sword lock), Chains (Locked using sword lock)"
    )
    print("You're chained to the floor")
    Room1Start = input("What do you want to do?: ")
    if Room1Start == "Pick Up Rock":
        if len(inventory) == 0 or "Rock" not in inventory:
            inventory.append("Rock")
            print("You have picked up a rock")
            Room1Command()
    else:
        do_something_else()