LinkButton和jquery

Question

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<script type="text/javascript">
    $(function () {
        $("[id*=btnDelete]").removeAttr("onclick");
        $("#dialog").dialog({
            modal: true,
            autoOpen: false,
            title: "Confirmation",
            width: 350,
            height: 160,
            buttons: [
                {
                    id: "Yes",
                    text: "Yes",
                    click: function () {
                      $("[id*=btnDelete]").attr("rel", "delete");
                        $("[id*=btnDelete]").click();
                    }
                },
                {
                    id: "No",
                    text: "No",
                    click: function () {
                        $(this).dialog('close');
                    }
                }
            ]
        });
      $("[id*=btnDelete]").click(function () {
            if ($(this).attr("rel") != "delete") {
                $('#dialog').dialog('open');
                return false;
            } else {
                __doPostBack(this.name, '');
            }
        });
    });
</script>
  <asp:LinkButton ID="btnDelete"   CssClass="ui-icon" runat="server"  OnClick="DeleteRecord" >
                  <div  class="icon-lougou"></div><br /> <span>logout</span></asp:LinkButton>

​

该对话框是显示，放置，不触发onclick，DeleteRecored不能在显示对话框之后触发onlick。

该对话框是显示，放置，不触发onclick，DeleteRecored不能在显示对话框之后触发onlick。

Answer 1

您可以使用OnClientClick属性：

<asp:LinkButton ID="btnDelete"   CssClass="ui-icon" runat="server"  OnClientClick="DeleteRecord();" >

根据文件：

OnClientClick属性用于设置要在单击Button控件时运行的客户端脚本