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社区首页 >问答首页 >PYMYSQL错误pymysql.err.ProgrammingError:(1064,“您的SQL语法中有错误")

PYMYSQL错误pymysql.err.ProgrammingError:(1064,“您的SQL语法中有错误")
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Stack Overflow用户
提问于 2022-01-27 11:29:17
回答 1查看 850关注 0票数 0

这是完整的错误

代码语言:javascript
复制
Traceback (most recent call last):
  File "Desktop/Work/RDS_LAMDA_Stuff/RDS_Node_Stuff/test.py", line 26, in <module>
    handler()
  File "Desktop/Work/RDS_LAMDA_Stuff/RDS_Node_Stuff/test.py", line 17, in handler
    cursor.execute('SELECT * FROM Reads')
  File "Desktop/Work/RDS_LAMDA_Stuff/RDS_Node_Stuff/pymysql/cursors.py", line 148, in execute
    result = self._query(query)
  File "Desktop/Work/RDS_LAMDA_Stuff/RDS_Node_Stuff/pymysql/cursors.py", line 310, in _query
    conn.query(q)
  File "Desktop/Work/RDS_LAMDA_Stuff/RDS_Node_Stuff/pymysql/connections.py", line 548, in query
    self._affected_rows = self._read_query_result(unbuffered=unbuffered)
  File "Desktop/Work/RDS_LAMDA_Stuff/RDS_Node_Stuff/pymysql/connections.py", line 775, in _read_query_result
    result.read()
  File "Desktop/Work/RDS_LAMDA_Stuff/RDS_Node_Stuff/pymysql/connections.py", line 1156, in read
    first_packet = self.connection._read_packet()
  File "Desktop/Work/RDS_LAMDA_Stuff/RDS_Node_Stuff/pymysql/connections.py", line 725, in _read_packet
    packet.raise_for_error()
  File "Desktop/Work/RDS_LAMDA_Stuff/RDS_Node_Stuff/pymysql/protocol.py", line 221, in raise_for_error
    err.raise_mysql_exception(self._data)
  File "Desktop/Work/RDS_LAMDA_Stuff/RDS_Node_Stuff/pymysql/err.py", line 143, in raise_mysql_exception
    raise errorclass(errno, errval)
pymysql.err.ProgrammingError: (1064, "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Reads' at line 1")

这里是我的代码

代码语言:javascript
复制
from multiprocessing import connection
import pymysql
from pymysql.cursors import Cursor

# RDS config
endpoint = '********'
username = '********'
password = '********'
database_name = '*********'

#connection config

connection = pymysql.connect(host=endpoint,user=username,passwd=password,db=database_name)

def handler():
    cursor = connection.cursor()
    cursor.execute('SELECT * FROM Reads')

    rows = cursor.fetchall()

    for row in rows:
        print("{0} {1} {2} {3}".format(row[0], row[1], row[2], row[3]))



handler()

我的数据库中还有另外两个表,当我查询它们时,它们工作得很好,但是这个表似乎是唯一一个导致错误的表。

如果这个太模糊的话,可以再多问一次。

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回答 1

Stack Overflow用户

回答已采纳

发布于 2022-01-27 11:33:00

在这种情况下,检查手册是值得的--读取是一个保留字,因此必须进行回拨--最好还是不要使用保留字,否则您将不得不永远记住在代码中回勾。

票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/70877814

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