用jq创建JSON

Question

我正在尝试从命令"lsb_release“的结果创建一个JSON文件

我所做的：

if [ -x "$(command -v lsb_release)" ]; then
    lsb_release -a  | jq  --raw-input 'split("\t") | { (.[0]) : .[1] }' > ubuntu_release.json
fi

结果是

{
  "Distributor ID:": "Ubuntu"
}

{
  "Description:": "Ubuntu 20.04.3 LTS"
}

{
  "Release:": "20.04"
}

{
  "Codename:": "focal"
}

但我想知道结果

[
    {
      "Distributor ID:": "Ubuntu"
    },
    {
      "Description:": "Ubuntu 20.04.3 LTS"
    },
    {
      "Release:": "20.04"
    },
    {
      "Codename:": "focal"
    }
]

有人能帮我吗？)

Answer 1

过滤器

reduce (inputs / ":\t") as [$key, $value] ({}; .+{($key): $value})

输入

Distributor ID: Ubuntu
Description:    Ubuntu 20.04.3 LTS
Release:    20.04
Codename:   focal

输出

{
  "Distributor ID": "Ubuntu",
  "Description": "Ubuntu 20.04.3 LTS",
  "Release": "20.04",
  "Codename": "focal"
}

请注意，来自$key和$value的inputs的每一行都是由reduce处理和组合的。

演示

https://jqplay.org/s/ZBvKf6vQ0F