Terraform --我如何将包含"for_each“参数的资源引用到另一个资源？

Question

我创建了一个使用for_each参数生成VM列表的资源。我很难将这个资源引用到我的web_private_group。

resource "google_compute_instance_group" "web_private_group" {
  name = "${format("%s","${var.gcp_resource_name}-${var.gcp_env}-vm-group")}"
  description = "Web servers instance group"
  zone = var.gcp_zone_1
  network = google_compute_network.vpc.self_link

  # I've added some attempts I've tried that do not work...
  instances = [
    //google_compute_instance.compute_engines.self_link
    //[for o in google_compute_instance.compute_engines : o.self_link]
    {for k, o in google_compute_instance.compute_engines : k => o.self_link}
    //google_compute_instance.web_private_2.self_link
  ]
    named_port {
    name = "http"
    port = "80"
  }
    named_port {
    name = "https"
    port = "443"
  }
}


# Create Google Cloud VMs 
resource "google_compute_instance" "compute_engines" {
  for_each = var.vm_instances
  name = "${format("%s","${var.gcp_resource_name}-${var.gcp_env}-each.value")}"
  machine_type = "e2-micro"
  zone         = var.gcp_zone_1
  tags         = ["ssh","http"]

  boot_disk {
    initialize_params {
      image = "debian-10"
    }
  }
}

variable "vm_instances" {
  description = "list of VM's"
  type        = set(string)
  default     = ["vm1", "vm2", "vm3"]
} 

如何正确地将compute_engines链接到web_private_group块中的web_private_group资源？

编辑:为了进一步澄清，我如何声明在我的compute_engines资源中存在多个实例的事实？

Answer 1

您可能只需要按照以下方式使用splat表达式：

instances = values(google_compute_instance.compute_engines)[*].id

此外，还可以使用for表达式：

instances = [for res in google_compute_instance.compute_engines: res.id]