Bash将变量分配给命令输出，该输出将是多个字串的列表。

Question

这就是我想要运行的脚本

bRules=(`aws s3api get-bucket-lifecycle-configuration --bucket x |  jq '.Rules[]'.ID`)
echo "*** Total number of LifecycleRules ****  ${#bRules[@]}"
for rule in "${bRules[@]}"
do
    echo "Bucket: x, Rule: $rule"
done

实际输出

*** Total number of LifecycleRules ****  6
 Bucket: x, Rule: This
 Bucket: x, Rule: is
 Bucket: x, Rule: Rule-1
 Bucket: x, Rule: This
 Bucket: x, Rule: is
 Bucket: x, Rule: Rule-2

预期产出：

*** Total number of LifecycleRules ****  2
Bucket: x, Rule: This is Rule-1
Bucket: x, Rule: This is Rule-2

在我的代码片段中需要更改什么才能获得所需的输出？我有点不知所措来解决这个问题。

Answer 1

不要依赖命令替换和分词。使用readarray (或者如果您愿意的话使用mapfile )和进程替换。

您的循环也可以简化为一个printf。

readarray -t bRules < <(aws s3api get-bucket-lifecycle-configuration --bucket x | jq '.Rules[]'.ID)
echo "*** Total number of LifecycleRules ****  ${#bRules[@]}"
printf 'Bucket: x, Rule: %s\n' "${bRules[@]}"

读巴什手册。