我有一个名为newspaper_cd的列,可以是A129或FHID。我需要首先从右边提取三个数字,然后在雪花中添加一个条件表达式。问题是当前列是字符串,即使正确的3位数是一个数字,它仍然被视为字符串。
case when is_real(to_variant(right(newspaper_cd,3))) = True then 1 else 0
--- I got all 0s, because it is a string column
--- If I change it for a number thinking about the case like A129
to_number(right(newspaper_cd,3))
--- 'HID' is not recognized for 'FHID'那我该怎么处理呢?谢谢。
发布于 2021-12-28 16:57:35
使用数
SELECT newspaper_cd, TRY_TO_NUMBER(right(newspaper_cd,3)) IS NOT NULL
FROM tab输出:
A129 True
FHID False发布于 2021-12-28 17:41:57
您还可以将SUBSTR应用于具有varchar的列,如下所示
select
CASE
WHEN IS_REAL(TO_NUMBER(substr(newspaper_cd, -3, 3))) = TRUE THEN 1
else 0
end;https://stackoverflow.com/questions/70509921
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