Zipfile:如何下载zipfile并保存而不解压？

Question

我想从url下载一个zipfile并保存到某个地方。我不想提取我的文件，这是我的问题。我有一个下载zipfile和提取文件的代码，但我只想下载和保存。我应该改变什么？

from urllib.request import urlopen
from zipfile import ZipFile


  zipurl = 'https://opendata.geoportal.gov.pl/prg/adresy/PunktyAdresowe/POLSKA.zip'
    with urlopen(zipurl) as zipresp:
        with ZipFile(BytesIO(zipresp.read())) as zfile:
            zfile.extractall(r'/home/gis/adresypolska')  




Error:

Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
  File "/usr/lib/python3.8/http/client.py", line 471, in read
    s = self._safe_read(self.length)
  File "/usr/lib/python3.8/http/client.py", line 612, in _safe_read
    data = self.fp.read(amt)
  File "/usr/lib/python3.8/socket.py", line 669, in readinto
    return self._sock.recv_into(b)
  File "/usr/lib/python3.8/ssl.py", line 1241, in recv_into
    return self.read(nbytes, buffer)
  File "/usr/lib/python3.8/ssl.py", line 1099, in read
    return self._sslobj.read(len, buffer)
OverflowError: signed integer is greater than maximum

Answer 1

只是根本不要使用ZipFile。你有了文件内容，写出来：

zipurl = 'https://opendata.geoportal.gov.pl/prg/adresy/PunktyAdresowe/POLSKA.zip'
with open('POLSKA.zip', 'wb') as f:
    f.write(urlopen(zipurl).read())

要以块的形式读取和保存，如果RAM较小，请执行以下操作：

with open('POLSKA.zip', 'wb') as f:
    with urlopen(zipurl) as zipresp:
        while True:
            chunk = zipresp.read(1024)
            if not chunk: break
            f.write(chunk)

这将在每次迭代中读取1024个字节，您应该根据需要进行相应的更改。