views.py
获取输出中的其他内容,而不是它中存在的值,我正在尝试,但不是简单地回答,请给我一些我认为这样的错误发生在:(instance=Task)中的建议。
from django.shortcuts import render
from django.http import *
from MYapp.models import *
from .form import *
def venue(request):
venue_list = Task.objects.all()
return render(request,'MYapp/venue.html',{'venue_list': venue_list})
def navebar(request):
return render(request,'MYapp/navebar.html')
def db(request,db_id):
venues = Task.objects.get(pk=db_id)
return render(request,'MYapp/db.html',{'venues': venues})
def search(request):
if request.method =="POST":
searched = request.POST.get('searched', False)
Tasks =Task.objects.filter( firstname__contains = searched)
return render(request,'MYapp/search.html',{'searched':searched, 'Tasks':Tasks})
else:
return render(request,'MYapp/search.html',{})
def update(request,db_id):
venues = Task.objects.get(pk=db_id)
form = TaskForm(request.POST or None, instance=Task)
return render(request,'MYapp/update.html',{'venues': venues,'form':form}) 发布于 2021-12-14 17:31:49
分配变量而不是类
def update(request,db_id):
venues = Task.objects.get(pk=db_id)
form = TaskForm(request.POST or None, instance=Task)
return render(request,'MYapp/update.html',{'venues':
venues,'form':form}) 执行此操作
def update(request,db_id):
venues = Task.objects.get(pk=db_id)
form = TaskForm(request.POST or None, instance=venues )
return render(request,'MYapp/update.html',{'venues':
venues,'form':form}) https://stackoverflow.com/questions/70346789
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